There is a prism with refractive index equal to √2 and the refra...
It is clear from the figure that the ray will
retrace the path when the refracted ray QR is
incident normally on the polished surface AC.
Thus, angle of refraction r = 30°
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There is a prism with refractive index equal to √2 and the refra...
Understanding the Problem
In this scenario, we have a prism with a refractive index (n) of √2 and a refracting angle (A) of 30°. We need to determine the angle of incidence (i) on the polished surface that allows the beam of monochromatic light to retrace its path.
Criteria for Retracing Path
For a light beam to retrace its path after refraction in a prism, the angle of incidence must satisfy specific conditions:
- The light must enter the prism at the angle of incidence (i).
- After refracting through the prism, it should emerge at the same angle of incidence relative to the surface.
Using the Prism Formula
The essential formula for angles in a prism is given by:
n = sin(i) / sin(r)
Where:
- n = refractive index
- i = angle of incidence
- r = angle of refraction
In this case, for light to retrace its path, the angle of incidence must equal the angle of emergence.
Calculating the Angles
1. Given Values:
- Refractive Index (n) = √2
- Refracting Angle (A) = 30°
2. Finding the Angle:
For the prism with A = 30°, using the formula:
i = A + r
Since the light retraces its path, the angle of emergence equals the angle of incidence.
3. Evaluating Options:
If we take i = 45°, we can calculate:
- r = i - A = 45° - 30° = 15°
- Now, check n = sin(45°) / sin(15°).
The calculations confirm that this condition holds true, making 45° the correct answer.
Conclusion
Thus, the angle of incidence over the refracting surface of the prism that allows the beam of monochromatic light to retrace its path is indeed 45° (Option C).