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The internal impedance of a source is 3 + j4 Ω, it is desired to supply maximum power to a resistive load. The load resistance should be
  • a)
    3 Ω
  • b)
    4 Ω
  • c)
    7 Ω
  • d)
    None of these
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The internal impedance of a source is 3 + j4 Ω, it is desired to...
According to maximum power transfer theorem in the AC circuit, to draw maximum power the load impedance must be complex conjugate of source circuit internal impedance.
Here purely resistive load is chosen, hence for maximum average power transfer, the load resistance is equal to the magnitude of source internal impedance.
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The internal impedance of a source is 3 + j4 Ω, it is desired to...
The internal impedance of a source is a complex number that represents the resistance and reactance of the source. In this case, the internal impedance is 3+j4.

The real part (3) represents the resistance of the source, while the imaginary part (j4) represents the reactance. The reactance can be either capacitive or inductive, depending on the sign of the imaginary part.

To calculate the magnitude of the impedance, we use the Pythagorean theorem:

|Z| = √(3² + 4²) = √(9 + 16) = √25 = 5

So the magnitude of the internal impedance is 5 ohms.

To calculate the phase angle of the impedance, we use the inverse tangent function:

θ = tan⁻¹(4/3) = 53.13°

So the phase angle of the internal impedance is 53.13 degrees.
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The internal impedance of a source is 3 + j4 Ω, it is desired to supply maximum power to a resistive load. The load resistance should bea)3 Ωb)4 Ωc)7 Ωd)None of theseCorrect answer is option 'D'. Can you explain this answer?
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