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A galvanometer of resistance 50 Ω is connectedto battery of 3V along with a resistance of 2950 Ωin series. A full scale deflection of 30 divisions isobtained in the galvanometer. In order to reducethis deflection to 20 divisions, the resistance inseries should be [2008]
  • a)
    5050 Ω
  • b)
    5550 Ω
  • c)
    6050 Ω
  • d)
    4450 Ω
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A galvanometer of resistance 50 Ω is connectedto battery of 3V a...
Total internal resistance = (50+2950)Ω
= 3000 Ω
Emf of the cell, ε = 3V
Current for full scale deflection of 30
divisions is 1.0 mA.
∴ Current for a deflection of 20 divisions
Let the resistance be x Ω. Then
= 4500 Ω
But the resistance of the galvanometer
is 50Ω
∴ Resistance to be added
= (4500 –50) Ω= 4450 Ω
 
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Most Upvoted Answer
A galvanometer of resistance 50 Ω is connectedto battery of 3V a...
Ohms is connected in series with a resistor of resistance 100 Ohms. The combination is connected across a battery of emf 12 V. Calculate the potential difference across the galvanometer.
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Read the following text and answer the following questions on the basis of the same: Galvanometer can sense/measure current. Improved mirror galvanometer was developed by William Thomson, later to become Lord Kelvin, in 1858. Thomson intended the instrument to read weak signal currents on very long submarine telegraph cables. The fundamental problems of transmitting/ receiving a signal through a lengthy submarine cable was that the electrical current tended to be very low (as little as 1/100,000th of a standard light bul b). So, it was very difficult to detect it. To solve the problem it was thought that larger amount of electric current would be sent through the line. But Thomson had a different approach. He thought the best response was to devise a device that could read faint signals. The galvanometer, first invented in 1802, was a means of detecting electric current. It consisted of a needle that was deflected by the magnetic field created by the electric current. But the galvanometers of the day couldn't detect the weak signals that came through a long underwater cable. But the improved version of galvanometer was highly sensitive to detect the lowest current. The mirror galvanometer consists of a long fine coil of silk-covered copper wire. In the heart of that coil, within a little air-chamber, a small round mirror is hung by a single fibre of floss silk, with four tiny magnets cemented to its back. A beam of light is thrown from a lamp upon the mirror, and reflected by it upon a white screen or scale a few feet distant, where it forms a bright spot of light; when there is no current on the instrument, the spot of light remains stationary at the zero position on the screen; but the instant a current traverses the long wire of the coil, the suspended magnets twist themselves horizontally out of their former position, the mirror is inclined with them, and the beam of light is deflected along the screen to one side or the other, according to the nature of the current. If a positive electric current gives a deflection to the right of zero, a negative current will give a deflection to the left of zero, and vice versa. The air in the little chamber surrounding the mirror is compressed, so as to act like a cushion, and deaden the movements of the mirror; the mirror is thus prevented from idly swinging about at each deflections.Mirror galvanometer was primarily used to

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A galvanometer of resistance 50 Ω is connectedto battery of 3V along with a resistance of 2950 Ωin series. A full scale deflection of 30 divisions isobtained in the galvanometer. In order to reducethis deflection to 20 divisions, the resistance inseries should be [2008]a)5050 Ωb)5550 Ωc)6050 Ωd)4450 ΩCorrect answer is option 'D'. Can you explain this answer?
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A galvanometer of resistance 50 Ω is connectedto battery of 3V along with a resistance of 2950 Ωin series. A full scale deflection of 30 divisions isobtained in the galvanometer. In order to reducethis deflection to 20 divisions, the resistance inseries should be [2008]a)5050 Ωb)5550 Ωc)6050 Ωd)4450 ΩCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A galvanometer of resistance 50 Ω is connectedto battery of 3V along with a resistance of 2950 Ωin series. A full scale deflection of 30 divisions isobtained in the galvanometer. In order to reducethis deflection to 20 divisions, the resistance inseries should be [2008]a)5050 Ωb)5550 Ωc)6050 Ωd)4450 ΩCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A galvanometer of resistance 50 Ω is connectedto battery of 3V along with a resistance of 2950 Ωin series. A full scale deflection of 30 divisions isobtained in the galvanometer. In order to reducethis deflection to 20 divisions, the resistance inseries should be [2008]a)5050 Ωb)5550 Ωc)6050 Ωd)4450 ΩCorrect answer is option 'D'. Can you explain this answer?.
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