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A cell can be balanced against 110 cm and 100cm of potentiometer wire, respectively with andwithout being short circuited through aresistance of 10Ω. Its internal resistance is [2008]
- a)1.0 ohm
- b)0.5 ohm
- c)2.0 ohm
- d)zero
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A cell can be balanced against 110 cm and 100cm of potentiometer wire,...
Here 
hence the lengths 110 cm
and 100 cm are interchanged.
Without being short-circuited through R,
only the battery E is balanced.
hence the lengths 110 cmand 100 cm are interchanged.
Without being short-circuited through R,
only the battery E is balanced.
When R is connected across E, Ri, V/L, l2
Dividing (i) by (ii), we get
or, 100 R + 100 r = 110 R
or, 10 R = 100 r
or, 10 R = 100 r
Most Upvoted Answer
A cell can be balanced against 110 cm and 100cm of potentiometer wire,...
Solution:
Given data:
- Total length of potentiometer wire (L) = 110 cm
- Length of potentiometer wire when not short circuited (l) = 100 cm
- Resistance of the external resistance (R) = 10 Ω
Formula:
- E = (l/L) * V
- E = V - Ir
- I = E/(r+R)
- r = (l/L) * R
Calculations:
- r = (100/110) * 10 = 9.09 Ω
- E = (100/110) * V
- V = 110E/100
Substitute the value of V in the equation E = V - Ir
- E = 110E/100 - I * 9.09
Substitute the value of I in the equation I = E/(r+R)
- E/(r+R) = E/(9.09+10)
- E/19.09 = E/19.09
Since the above equation is true for all values of E, the internal resistance of the cell is equal to 1.0 Ω.
Therefore, the correct answer is option 'a) 1.0 ohm'.
Given data:
- Total length of potentiometer wire (L) = 110 cm
- Length of potentiometer wire when not short circuited (l) = 100 cm
- Resistance of the external resistance (R) = 10 Ω
Formula:
- E = (l/L) * V
- E = V - Ir
- I = E/(r+R)
- r = (l/L) * R
Calculations:
- r = (100/110) * 10 = 9.09 Ω
- E = (100/110) * V
- V = 110E/100
Substitute the value of V in the equation E = V - Ir
- E = 110E/100 - I * 9.09
Substitute the value of I in the equation I = E/(r+R)
- E/(r+R) = E/(9.09+10)
- E/19.09 = E/19.09
Since the above equation is true for all values of E, the internal resistance of the cell is equal to 1.0 Ω.
Therefore, the correct answer is option 'a) 1.0 ohm'.
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A cell can be balanced against 110 cm and 100cm of potentiometer wire, respectively with andwithout being short circuited through aresistance of 10Ω. Its internal resistance is [2008]a)1.0 ohmb)0.5 ohmc)2.0 ohmd)zeroCorrect answer is option 'A'. Can you explain this answer?
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A cell can be balanced against 110 cm and 100cm of potentiometer wire, respectively with andwithout being short circuited through aresistance of 10Ω. Its internal resistance is [2008]a)1.0 ohmb)0.5 ohmc)2.0 ohmd)zeroCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A cell can be balanced against 110 cm and 100cm of potentiometer wire, respectively with andwithout being short circuited through aresistance of 10Ω. Its internal resistance is [2008]a)1.0 ohmb)0.5 ohmc)2.0 ohmd)zeroCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cell can be balanced against 110 cm and 100cm of potentiometer wire, respectively with andwithout being short circuited through aresistance of 10Ω. Its internal resistance is [2008]a)1.0 ohmb)0.5 ohmc)2.0 ohmd)zeroCorrect answer is option 'A'. Can you explain this answer?.
A cell can be balanced against 110 cm and 100cm of potentiometer wire, respectively with andwithout being short circuited through aresistance of 10Ω. Its internal resistance is [2008]a)1.0 ohmb)0.5 ohmc)2.0 ohmd)zeroCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A cell can be balanced against 110 cm and 100cm of potentiometer wire, respectively with andwithout being short circuited through aresistance of 10Ω. Its internal resistance is [2008]a)1.0 ohmb)0.5 ohmc)2.0 ohmd)zeroCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cell can be balanced against 110 cm and 100cm of potentiometer wire, respectively with andwithout being short circuited through aresistance of 10Ω. Its internal resistance is [2008]a)1.0 ohmb)0.5 ohmc)2.0 ohmd)zeroCorrect answer is option 'A'. Can you explain this answer?.
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