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A steady current of 1.5 amp flows through acopper voltameter for 10 minutes. If the electrochemical equivalent of copper is30 × 10–5 g coulomb–1, the mass of copperdeposited on the electrode will be [2007]
  • a)
    0.50 g
  • b)
    0.67 g
  • c)
    0.27 g
  • d)
    0.40 g.
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A steady current of 1.5 amp flows through acopper voltameter for 10 mi...
We have, m = ZIt
where, Z is the electrochemical equivalent
of copper.
⇒ m = 30 x10-5 x1.5 x10 x 60
= 0.27 gm.
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Most Upvoted Answer
A steady current of 1.5 amp flows through acopper voltameter for 10 mi...
G/amp-hour, calculate the mass of copper deposited.

First, calculate the total charge passed through the voltameter:
Q = I x t
Q = 1.5 amp x 10 minutes
Q = 1.5 amp x 10 minutes x 60 seconds/minute
Q = 900 Coulombs

Next, calculate the mass of copper deposited using the electrochemical equivalent:
Mass = (Q / 3600) x equivalent
Mass = (900 / 3600) x 30
Mass = 0.25 x 30
Mass = 7.5 grams

Therefore, the mass of copper deposited in the voltameter is 7.5 grams.
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A steady current of 1.5 amp flows through acopper voltameter for 10 minutes. If the electrochemical equivalent of copper is30 × 10–5 g coulomb–1, the mass of copperdeposited on the electrode will be [2007]a)0.50 gb)0.67 gc)0.27 gd)0.40 g.Correct answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A steady current of 1.5 amp flows through acopper voltameter for 10 minutes. If the electrochemical equivalent of copper is30 × 10–5 g coulomb–1, the mass of copperdeposited on the electrode will be [2007]a)0.50 gb)0.67 gc)0.27 gd)0.40 g.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A steady current of 1.5 amp flows through acopper voltameter for 10 minutes. If the electrochemical equivalent of copper is30 × 10–5 g coulomb–1, the mass of copperdeposited on the electrode will be [2007]a)0.50 gb)0.67 gc)0.27 gd)0.40 g.Correct answer is option 'C'. Can you explain this answer?.
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