Consider the following statements:A real gas obeys perfect gas law at ...
In Perfect gas intermolecular attraction is zero. It will be only possible when intermolecular distance will be too high. High temperature or low pressure or both cause high intermolecular distance so choice 1 and 3.
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Consider the following statements:A real gas obeys perfect gas law at ...
Explanation:
Perfect gas law is given by PV = nRT, where P is pressure, V is volume, n is the number of moles of the gas, R is the universal gas constant and T is the temperature.
Real gases, unlike ideal gases, do not obey perfect gas law exactly. They have intermolecular forces between the gas molecules which affect their behavior. However, at certain conditions, they behave like ideal gases and obey perfect gas law.
1. High temperature:
At high temperature, the kinetic energy of the gas molecules increases, which makes them move faster and collide more frequently. This reduces the effect of intermolecular forces and makes the gas behave like an ideal gas. Therefore, a real gas obeys perfect gas law at high temperature.
2. High-pressure:
At high pressure, the volume occupied by the gas molecules becomes significant compared to the total volume of the gas. This results in a decrease in the average distance between the gas molecules, which increases the effect of intermolecular forces. Therefore, real gases do not obey perfect gas law at high pressure.
3. Low pressure:
At low pressure, the distance between the gas molecules becomes significant compared to their size. This reduces the effect of intermolecular forces and makes the gas behave like an ideal gas. Therefore, a real gas obeys perfect gas law at low pressure.
Conclusion:
From the above discussion, it is clear that a real gas obeys perfect gas law at high temperature and low pressure. Therefore, option B (1 and 3) is the correct answer.
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