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The energy of an electron in the Bohr’s first orbit of Hatom is –13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr’s orbits of hydrogen is(are)
- a)–3.4 eV
- b)–4.2 eV
- c)–6.8 eV
- d)+6.8 eV
Correct answer is option 'A'. Can you explain this answer?
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The energy of an electron in the Bohr’s first orbit of Hatom is ...
-3.4 answer hai.yahan per exited state kuch nahi diya hua Hai.lekin hum agar hydrogen atom ka pehla excited state ko consider karenge then our n=2 hoga.so as we know -13.6 /n^2 ,yahan per agar tum n ka value put karogi to -3.4 ans ayega.-3.4 ko chodne ke baad or jo 3 options hain wo kisi bhi exited state ka energy nahi Hai.so ans is a.I hope u understand
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The energy of an electron in the Bohr’s first orbit of Hatom is ...
Understanding Bohr's Model of Hydrogen Atom
The Bohr model describes the energy levels of electrons in a hydrogen atom. The energy of an electron in the n-th orbit is given by the formula:
Energy (E) = -13.6 eV / n²
where 'n' is the principal quantum number (orbit number).
Energy in the First Orbit
- For n = 1 (first orbit), the energy is:
- E1 = -13.6 eV / 1² = -13.6 eV
Calculating Energy for Excited States
- For excited states, we need to consider different values of n.
1. n = 2 (Second Orbit):
- E2 = -13.6 eV / 2² = -13.6 eV / 4 = -3.4 eV
2. n = 3 (Third Orbit):
- E3 = -13.6 eV / 3² = -13.6 eV / 9 = -1.51 eV (not a given option)
3. n = 4 (Fourth Orbit):
- E4 = -13.6 eV / 4² = -13.6 eV / 16 = -0.85 eV (not a given option)
Energy Values of Excited States
- The only relevant excited state energy from the options provided is for n = 2:
- -3.4 eV (correct answer)
- Other options like -4.2 eV, -6.8 eV, and +6.8 eV do not correspond to allowed energy states in the Bohr model for hydrogen.
Conclusion
- The possible energy value for the first excited state of the electron in the hydrogen atom according to Bohr’s model is -3.4 eV, confirming option 'A' as the correct answer.
The Bohr model describes the energy levels of electrons in a hydrogen atom. The energy of an electron in the n-th orbit is given by the formula:
Energy (E) = -13.6 eV / n²
where 'n' is the principal quantum number (orbit number).
Energy in the First Orbit
- For n = 1 (first orbit), the energy is:
- E1 = -13.6 eV / 1² = -13.6 eV
Calculating Energy for Excited States
- For excited states, we need to consider different values of n.
1. n = 2 (Second Orbit):
- E2 = -13.6 eV / 2² = -13.6 eV / 4 = -3.4 eV
2. n = 3 (Third Orbit):
- E3 = -13.6 eV / 3² = -13.6 eV / 9 = -1.51 eV (not a given option)
3. n = 4 (Fourth Orbit):
- E4 = -13.6 eV / 4² = -13.6 eV / 16 = -0.85 eV (not a given option)
Energy Values of Excited States
- The only relevant excited state energy from the options provided is for n = 2:
- -3.4 eV (correct answer)
- Other options like -4.2 eV, -6.8 eV, and +6.8 eV do not correspond to allowed energy states in the Bohr model for hydrogen.
Conclusion
- The possible energy value for the first excited state of the electron in the hydrogen atom according to Bohr’s model is -3.4 eV, confirming option 'A' as the correct answer.
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The energy of an electron in the Bohr’s first orbit of Hatom is –13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr’s orbits of hydrogen is(are)a)–3.4 eVb)–4.2 eVc)–6.8 eVd)+6.8 eVCorrect answer is option 'A'. Can you explain this answer?
Question Description
The energy of an electron in the Bohr’s first orbit of Hatom is –13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr’s orbits of hydrogen is(are)a)–3.4 eVb)–4.2 eVc)–6.8 eVd)+6.8 eVCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The energy of an electron in the Bohr’s first orbit of Hatom is –13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr’s orbits of hydrogen is(are)a)–3.4 eVb)–4.2 eVc)–6.8 eVd)+6.8 eVCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The energy of an electron in the Bohr’s first orbit of Hatom is –13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr’s orbits of hydrogen is(are)a)–3.4 eVb)–4.2 eVc)–6.8 eVd)+6.8 eVCorrect answer is option 'A'. Can you explain this answer?.
The energy of an electron in the Bohr’s first orbit of Hatom is –13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr’s orbits of hydrogen is(are)a)–3.4 eVb)–4.2 eVc)–6.8 eVd)+6.8 eVCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The energy of an electron in the Bohr’s first orbit of Hatom is –13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr’s orbits of hydrogen is(are)a)–3.4 eVb)–4.2 eVc)–6.8 eVd)+6.8 eVCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The energy of an electron in the Bohr’s first orbit of Hatom is –13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr’s orbits of hydrogen is(are)a)–3.4 eVb)–4.2 eVc)–6.8 eVd)+6.8 eVCorrect answer is option 'A'. Can you explain this answer?.
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