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A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m/s2 the horizontal force that he is applying on the pole is
- a)250 N
- b)200 N
- c)500 N
- d)50 N
Correct answer is option 'C'. Can you explain this answer?
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A boy of mass 40 kg is climbing a vertical pole at a constant speed. I...
Here, μ= 0. 8
Let F be horizontal force that the boy is applying on the pole.
The various forces are acting on the boy as shown in the below figure.
Frictional force.
The various forces are acting on the boy as shown in the below figure.
Frictional force.
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A boy of mass 40 kg is climbing a vertical pole at a constant speed. I...
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A boy of mass 40 kg is climbing a vertical pole at a constant speed. I...
Given:
Mass of the boy, m = 40 kg
Coefficient of friction, μ = 0.8
Acceleration due to gravity, g = 10 m/s^2
To find:
The horizontal force that the boy is applying on the pole.
Explanation:
When the boy is climbing the pole at a constant speed, the frictional force between his palms and the pole balances the gravitational force acting on him. This frictional force can be calculated using the formula:
Frictional force = μ * Normal force
1. Normal force:
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal to the weight of the boy, which is given by:
Normal force = mass * acceleration due to gravity
Normal force = 40 kg * 10 m/s^2
Normal force = 400 N
2. Frictional force:
Using the given coefficient of friction, the frictional force can be calculated as:
Frictional force = μ * Normal force
Frictional force = 0.8 * 400 N
Frictional force = 320 N
3. Horizontal force:
The horizontal force that the boy is applying on the pole is equal to the frictional force, as it is the force required to balance the gravitational force. Therefore, the horizontal force is:
Horizontal force = Frictional force
Horizontal force = 320 N
Therefore, the horizontal force that the boy is applying on the pole is 320 N, which corresponds to option C.
Mass of the boy, m = 40 kg
Coefficient of friction, μ = 0.8
Acceleration due to gravity, g = 10 m/s^2
To find:
The horizontal force that the boy is applying on the pole.
Explanation:
When the boy is climbing the pole at a constant speed, the frictional force between his palms and the pole balances the gravitational force acting on him. This frictional force can be calculated using the formula:
Frictional force = μ * Normal force
1. Normal force:
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal to the weight of the boy, which is given by:
Normal force = mass * acceleration due to gravity
Normal force = 40 kg * 10 m/s^2
Normal force = 400 N
2. Frictional force:
Using the given coefficient of friction, the frictional force can be calculated as:
Frictional force = μ * Normal force
Frictional force = 0.8 * 400 N
Frictional force = 320 N
3. Horizontal force:
The horizontal force that the boy is applying on the pole is equal to the frictional force, as it is the force required to balance the gravitational force. Therefore, the horizontal force is:
Horizontal force = Frictional force
Horizontal force = 320 N
Therefore, the horizontal force that the boy is applying on the pole is 320 N, which corresponds to option C.
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A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m/s2 the horizontal force that he is applying on the pole isa)250 Nb)200 Nc)500 Nd)50 NCorrect answer is option 'C'. Can you explain this answer?
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A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m/s2 the horizontal force that he is applying on the pole isa)250 Nb)200 Nc)500 Nd)50 NCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m/s2 the horizontal force that he is applying on the pole isa)250 Nb)200 Nc)500 Nd)50 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m/s2 the horizontal force that he is applying on the pole isa)250 Nb)200 Nc)500 Nd)50 NCorrect answer is option 'C'. Can you explain this answer?.
A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m/s2 the horizontal force that he is applying on the pole isa)250 Nb)200 Nc)500 Nd)50 NCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m/s2 the horizontal force that he is applying on the pole isa)250 Nb)200 Nc)500 Nd)50 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A boy of mass 40 kg is climbing a vertical pole at a constant speed. If the coefficient of friction between his palms and the pole is 0.8 and g = 10 m/s2 the horizontal force that he is applying on the pole isa)250 Nb)200 Nc)500 Nd)50 NCorrect answer is option 'C'. Can you explain this answer?.
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