Two Block A and B of masses 5 kg and 3kg respectively rest on a smooth...
Two Block A and B of masses 5 kg and 3kg respectively rest on a smooth...
Problem Statement:
Two blocks, A and B, with masses 5 kg and 3 kg respectively, rest on a smooth horizontal surface. Block B is placed on top of block A. The coefficient of friction between block A and B is 0.5. We need to determine the maximum horizontal force that can be applied to block A without causing relative slipping between the blocks.
Solution:
1. Free Body Diagrams:
To solve this problem, let's start by drawing the free body diagrams for both blocks A and B.
For block A:
- There is a gravitational force acting downwards (mg).
- There is a normal force exerted by block B (N).
- There is a frictional force between block A and B (f).
For block B:
- There is a gravitational force acting downwards (mg).
- There is a normal force exerted by the surface (N).
2. Equations of Motion:
Now, let's analyze the forces acting on block A.
Forces in the vertical direction:
- N - mg = 0 (Since block A is not moving vertically)
Forces in the horizontal direction:
- f - F = ma (Newton's second law, where F is the applied force and a is the acceleration of block A)
For block B, since it is not moving horizontally, the sum of forces in the horizontal direction is zero.
3. Frictional Force:
The frictional force (f) between block A and B can be calculated using the equation:
f = μN
Where μ is the coefficient of friction and N is the normal force. Since the normal force (N) is equal to the weight of block B (mg), we can rewrite the equation as:
f = μmg
4. Maximum Applied Force:
To find the maximum force (F) that can be applied to block A without causing relative slipping between the blocks, we need to consider the maximum frictional force that can be exerted between the blocks.
The maximum frictional force (f_max) is given by:
f_max = μN = μmg
Therefore, the maximum force (F) that can be applied to block A is equal to the maximum frictional force:
F = f_max = μmg
Substituting the given values, we have:
F = 0.5 * 5 kg * 9.8 m/s^2
Simplifying the equation, we find:
F = 24.5 N
Therefore, the maximum horizontal force that can be applied to block A without causing relative slipping between the blocks is 24.5 Newtons.
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