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A 8kg block (A) is placed on 2kg block (B) which rests on the table . Coefficient of friction between a and b is 0.2 and between b and table is 0.2 .A 60N horizontal force is applied on the block a , then the friction force between a and b is ?
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A 8kg block (A) is placed on 2kg block (B) which rests on the table . ...
Solution:
Given:
- Mass of block A = 8 kg
- Mass of block B = 2 kg
- Coefficient of friction between A and B, μAB = 0.2
- Coefficient of friction between B and table, μBT = 0.2
- Applied force, F = 60 N
To find:
- Friction force between A and B, fAB
Steps:
1. Draw a free-body diagram of block A and B.
2. Calculate the weight of each block, W = m * g, where m is the mass of the block and g is the acceleration due to gravity.
- Weight of block A, WA = 8 kg * 9.8 m/s^2 = 78.4 N
- Weight of block B, WB = 2 kg * 9.8 m/s^2 = 19.6 N
3. Determine the normal force acting on block A and B.
- Normal force on block A, NA = WB + WA = 98 N
- Normal force on block B, NB = WB = 19.6 N
4. Calculate the maximum friction force that can act between A and B and between B and the table.
- Maximum friction force between A and B, fABmax = μAB * NA = 0.2 * 98 N = 19.6 N
- Maximum friction force between B and table, fBTmax = μBT * NB = 0.2 * 19.6 N = 3.92 N
5. Determine if the applied force can overcome the friction force between A and B and between B and the table.
- Friction force between A and B, fAB ≤ fABmax
- Friction force between B and table, fBT ≤ fBTmax
6. Calculate the net force acting on block A.
- Net force on block A, FA = F - fAB
7. Determine if block A will move.
- If FA > 0, block A will move.
- If FA ≤ 0, block A will not move.
8. Calculate the friction force between A and B.
- If block A is moving, fAB = fABmax.
- If block A is not moving, fAB = FA.
Final Answer:
The friction force between A and B is 19.6 N.
Explanation:
When a horizontal force is applied to block A, the friction force between A and B opposes the motion of block A. The friction force between B and the table also opposes the motion of block A. The applied force must be greater than the friction force to overcome the friction and move the blocks. If the applied force is less than the friction force, the blocks will not move.
Given:
- Mass of block A = 8 kg
- Mass of block B = 2 kg
- Coefficient of friction between A and B, μAB = 0.2
- Coefficient of friction between B and table, μBT = 0.2
- Applied force, F = 60 N
To find:
- Friction force between A and B, fAB
Steps:
1. Draw a free-body diagram of block A and B.
2. Calculate the weight of each block, W = m * g, where m is the mass of the block and g is the acceleration due to gravity.
- Weight of block A, WA = 8 kg * 9.8 m/s^2 = 78.4 N
- Weight of block B, WB = 2 kg * 9.8 m/s^2 = 19.6 N
3. Determine the normal force acting on block A and B.
- Normal force on block A, NA = WB + WA = 98 N
- Normal force on block B, NB = WB = 19.6 N
4. Calculate the maximum friction force that can act between A and B and between B and the table.
- Maximum friction force between A and B, fABmax = μAB * NA = 0.2 * 98 N = 19.6 N
- Maximum friction force between B and table, fBTmax = μBT * NB = 0.2 * 19.6 N = 3.92 N
5. Determine if the applied force can overcome the friction force between A and B and between B and the table.
- Friction force between A and B, fAB ≤ fABmax
- Friction force between B and table, fBT ≤ fBTmax
6. Calculate the net force acting on block A.
- Net force on block A, FA = F - fAB
7. Determine if block A will move.
- If FA > 0, block A will move.
- If FA ≤ 0, block A will not move.
8. Calculate the friction force between A and B.
- If block A is moving, fAB = fABmax.
- If block A is not moving, fAB = FA.
Final Answer:
The friction force between A and B is 19.6 N.
Explanation:
When a horizontal force is applied to block A, the friction force between A and B opposes the motion of block A. The friction force between B and the table also opposes the motion of block A. The applied force must be greater than the friction force to overcome the friction and move the blocks. If the applied force is less than the friction force, the blocks will not move.
Community Answer
A 8kg block (A) is placed on 2kg block (B) which rests on the table . ...
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A 8kg block (A) is placed on 2kg block (B) which rests on the table . Coefficient of friction between a and b is 0.2 and between b and table is 0.2 .A 60N horizontal force is applied on the block a , then the friction force between a and b is ?
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A 8kg block (A) is placed on 2kg block (B) which rests on the table . Coefficient of friction between a and b is 0.2 and between b and table is 0.2 .A 60N horizontal force is applied on the block a , then the friction force between a and b is ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A 8kg block (A) is placed on 2kg block (B) which rests on the table . Coefficient of friction between a and b is 0.2 and between b and table is 0.2 .A 60N horizontal force is applied on the block a , then the friction force between a and b is ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 8kg block (A) is placed on 2kg block (B) which rests on the table . Coefficient of friction between a and b is 0.2 and between b and table is 0.2 .A 60N horizontal force is applied on the block a , then the friction force between a and b is ?.
A 8kg block (A) is placed on 2kg block (B) which rests on the table . Coefficient of friction between a and b is 0.2 and between b and table is 0.2 .A 60N horizontal force is applied on the block a , then the friction force between a and b is ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A 8kg block (A) is placed on 2kg block (B) which rests on the table . Coefficient of friction between a and b is 0.2 and between b and table is 0.2 .A 60N horizontal force is applied on the block a , then the friction force between a and b is ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 8kg block (A) is placed on 2kg block (B) which rests on the table . Coefficient of friction between a and b is 0.2 and between b and table is 0.2 .A 60N horizontal force is applied on the block a , then the friction force between a and b is ?.
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