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The coefficient of static friction μ  between block A of mass 2kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless (g = 10 m/s2
  • a)
    2.0kg  
  • b)
    4.0 kg 
  • c)
    0.2 kg  
  • d)
    0.4 kg
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The coefficient of static frictionμbetween block A of mass 2kg an...
For the equilibrium,  mBg = μmAg
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The coefficient of static frictionμbetween block A of mass 2kg and the table as shown in the figure is0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless (g = 10 m/s2)a)2.0kg b)4.0 kgc)0.2 kg d)0.4 kgCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The coefficient of static frictionμbetween block A of mass 2kg and the table as shown in the figure is0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless (g = 10 m/s2)a)2.0kg b)4.0 kgc)0.2 kg d)0.4 kgCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coefficient of static frictionμbetween block A of mass 2kg and the table as shown in the figure is0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless (g = 10 m/s2)a)2.0kg b)4.0 kgc)0.2 kg d)0.4 kgCorrect answer is option 'D'. Can you explain this answer?.
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