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If x, v and a denote the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period T, then, which of the following does not change with time?
  • a)
    aT/x
  • b)
    aT + 2πv
  • c)
    aT/v
  • d)
    a2T2 + 4p2v2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If x, v and a denote the displacement, the velocity and the accelerati...
For an SHM, the acceleration a = -ω2x where ω2 is a constant. Therefore a/x  is a constant. The time period
T is also constant. Therefor aT/x is a constant.
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Most Upvoted Answer
If x, v and a denote the displacement, the velocity and the accelerati...
B) T
The time period of a particle executing simple harmonic motion remains constant and does not change with time. Therefore, option b) T does not change with time. Option a) aT/x and option c) 2π/T both change with time as the displacement, velocity, and acceleration of the particle vary with time.
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