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If a wire conductor of 0.2-ohm resistance is doubled in length, its resistance becomes
- a)0.4 ohm
- b)0.8 ohm
- c)0.6 ohm
- d)1.2 ohm
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
If a wire conductor of 0.2-ohm resistance is doubled in length, its re...
Given that resistance of a conductor = 0.2 Ω
We know that resistance of a conductor is given by
Where ρ is resistivity
l is length
A is cross-sectional area
Given that, the length becomes double
The new resistance will become twice of the previous.
New resistance = 2 × 0.2 = 0.4 Ω
We know that resistance of a conductor is given by
Where ρ is resistivity
l is length
A is cross-sectional area
Given that, the length becomes double
The new resistance will become twice of the previous.
New resistance = 2 × 0.2 = 0.4 Ω
Most Upvoted Answer
If a wire conductor of 0.2-ohm resistance is doubled in length, its re...
Explanation:
When the length of a wire conductor is doubled, its resistance also doubles. This concept is based on the relationship between resistance, length, and resistivity.
Relationship between resistance, length, and resistivity:
The resistance of a wire conductor is directly proportional to its length and resistivity, and inversely proportional to its cross-sectional area. This relationship is given by the formula:
Resistance = (Resistivity * Length) / Cross-sectional area
Where:
- Resistance is measured in ohms (Ω)
- Resistivity is a property of the material and is measured in ohm-meters (Ω·m)
- Length is measured in meters (m)
- Cross-sectional area is measured in square meters (m²)
Given:
Resistance of the wire conductor = 0.2 ohms
Analysis:
If the length of the wire conductor is doubled, the new length becomes 2L, where L is the original length.
Using the formula for resistance, we can write the equation as:
0.2 ohms = (Resistivity * 2L) / Cross-sectional area
Since the resistivity and cross-sectional area of the wire conductor remain constant, we can simplify the equation to:
0.2 ohms = (Resistivity * 2L) / Cross-sectional area
Therefore, the resistance of the wire conductor after doubling its length is 0.4 ohms.
Conclusion:
When a wire conductor of 0.2-ohm resistance is doubled in length, its resistance becomes 0.4 ohms.
When the length of a wire conductor is doubled, its resistance also doubles. This concept is based on the relationship between resistance, length, and resistivity.
Relationship between resistance, length, and resistivity:
The resistance of a wire conductor is directly proportional to its length and resistivity, and inversely proportional to its cross-sectional area. This relationship is given by the formula:
Resistance = (Resistivity * Length) / Cross-sectional area
Where:
- Resistance is measured in ohms (Ω)
- Resistivity is a property of the material and is measured in ohm-meters (Ω·m)
- Length is measured in meters (m)
- Cross-sectional area is measured in square meters (m²)
Given:
Resistance of the wire conductor = 0.2 ohms
Analysis:
If the length of the wire conductor is doubled, the new length becomes 2L, where L is the original length.
Using the formula for resistance, we can write the equation as:
0.2 ohms = (Resistivity * 2L) / Cross-sectional area
Since the resistivity and cross-sectional area of the wire conductor remain constant, we can simplify the equation to:
0.2 ohms = (Resistivity * 2L) / Cross-sectional area
Therefore, the resistance of the wire conductor after doubling its length is 0.4 ohms.
Conclusion:
When a wire conductor of 0.2-ohm resistance is doubled in length, its resistance becomes 0.4 ohms.
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If a wire conductor of 0.2-ohm resistance is doubled in length, its resistance becomesa)0.4 ohmb)0.8 ohmc)0.6 ohmd)1.2 ohmCorrect answer is option 'A'. Can you explain this answer?
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