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Generally β-[D] glucose in more stable under H2O. But the solvent is changed to Cyclohexanol under Cyclohexanol. The stable form (major contribution) would be:
  • a)
    α-D-glucopyranose
  • b)
    D-glucose (open chain form)
  • c)
    β-D-glucopyranose
  • d)
    α and β will be 1:1 ratio.
Correct answer is option 'A'. Can you explain this answer?
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Generally β-[D] glucose in more stable under H2O. But the solvent...
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Generally β-[D] glucose in more stable under H2O. But the solvent is changed to Cyclohexanol under Cyclohexanol. The stable form (major contribution) would be:a)α-D-glucopyranoseb)D-glucose (open chain form)c)β-D-glucopyranosed)α and β will be 1:1 ratio.Correct answer is option 'A'. Can you explain this answer?
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Generally β-[D] glucose in more stable under H2O. But the solvent is changed to Cyclohexanol under Cyclohexanol. The stable form (major contribution) would be:a)α-D-glucopyranoseb)D-glucose (open chain form)c)β-D-glucopyranosed)α and β will be 1:1 ratio.Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Generally β-[D] glucose in more stable under H2O. But the solvent is changed to Cyclohexanol under Cyclohexanol. The stable form (major contribution) would be:a)α-D-glucopyranoseb)D-glucose (open chain form)c)β-D-glucopyranosed)α and β will be 1:1 ratio.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Generally β-[D] glucose in more stable under H2O. But the solvent is changed to Cyclohexanol under Cyclohexanol. The stable form (major contribution) would be:a)α-D-glucopyranoseb)D-glucose (open chain form)c)β-D-glucopyranosed)α and β will be 1:1 ratio.Correct answer is option 'A'. Can you explain this answer?.
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