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200cm3 of NH3 completely decomposed to N2 and H2 volume of the reaction mixture under same condition temperature and pressure would be (A) 200 cm3 (B) 600 cm3 (C) 400 cm3 (D) 500 cm3?
Most Upvoted Answer
200cm3 of NH3 completely decomposed to N2 and H2 volume of the reactio...
Given:
- Volume of NH3 = 200 cm3
- NH3 decomposes completely into N2 and H2
To find:
The volume of the reaction mixture under the same conditions.
Solution:
1. Balanced Equation:
The balanced equation for the decomposition of NH3 is:
2NH3 -> N2 + 3H2
2. Stoichiometry:
From the balanced equation, we can see that for every 2 moles of NH3, we get 1 mole of N2 and 3 moles of H2.
Therefore, the ratio of volumes is:
2 volumes of NH3 -> 1 volume of N2 + 3 volumes of H2
3. Volume Conversion:
Since the volume of NH3 is given as 200 cm3, we can calculate the volume of the reaction mixture using the volume ratio obtained from stoichiometry.
Volume of N2 = (1/2) * 200 cm3 = 100 cm3
Volume of H2 = (3/2) * 200 cm3 = 300 cm3
4. Total Volume:
The total volume of the reaction mixture is the sum of the volumes of N2 and H2.
Total Volume = Volume of N2 + Volume of H2
Total Volume = 100 cm3 + 300 cm3
Total Volume = 400 cm3
5. Answer:
Therefore, the volume of the reaction mixture under the same conditions would be 400 cm3. Hence, the correct option is (C) 400 cm3.
- Volume of NH3 = 200 cm3
- NH3 decomposes completely into N2 and H2
To find:
The volume of the reaction mixture under the same conditions.
Solution:
1. Balanced Equation:
The balanced equation for the decomposition of NH3 is:
2NH3 -> N2 + 3H2
2. Stoichiometry:
From the balanced equation, we can see that for every 2 moles of NH3, we get 1 mole of N2 and 3 moles of H2.
Therefore, the ratio of volumes is:
2 volumes of NH3 -> 1 volume of N2 + 3 volumes of H2
3. Volume Conversion:
Since the volume of NH3 is given as 200 cm3, we can calculate the volume of the reaction mixture using the volume ratio obtained from stoichiometry.
Volume of N2 = (1/2) * 200 cm3 = 100 cm3
Volume of H2 = (3/2) * 200 cm3 = 300 cm3
4. Total Volume:
The total volume of the reaction mixture is the sum of the volumes of N2 and H2.
Total Volume = Volume of N2 + Volume of H2
Total Volume = 100 cm3 + 300 cm3
Total Volume = 400 cm3
5. Answer:
Therefore, the volume of the reaction mixture under the same conditions would be 400 cm3. Hence, the correct option is (C) 400 cm3.
Community Answer
200cm3 of NH3 completely decomposed to N2 and H2 volume of the reactio...
400cm3
2 moles of nh3 = 200cm3
1 mole of nh3=100cm3
2nh3 gives n2 + 3h2
total moles of gas is 4
1 mole of gas at stp is 100cm3
4 mole of gas at stp is 400cm3
2 moles of nh3 = 200cm3
1 mole of nh3=100cm3
2nh3 gives n2 + 3h2
total moles of gas is 4
1 mole of gas at stp is 100cm3
4 mole of gas at stp is 400cm3
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200cm3 of NH3 completely decomposed to N2 and H2 volume of the reaction mixture under same condition temperature and pressure would be (A) 200 cm3 (B) 600 cm3 (C) 400 cm3 (D) 500 cm3?
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200cm3 of NH3 completely decomposed to N2 and H2 volume of the reaction mixture under same condition temperature and pressure would be (A) 200 cm3 (B) 600 cm3 (C) 400 cm3 (D) 500 cm3? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 200cm3 of NH3 completely decomposed to N2 and H2 volume of the reaction mixture under same condition temperature and pressure would be (A) 200 cm3 (B) 600 cm3 (C) 400 cm3 (D) 500 cm3? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 200cm3 of NH3 completely decomposed to N2 and H2 volume of the reaction mixture under same condition temperature and pressure would be (A) 200 cm3 (B) 600 cm3 (C) 400 cm3 (D) 500 cm3?.
200cm3 of NH3 completely decomposed to N2 and H2 volume of the reaction mixture under same condition temperature and pressure would be (A) 200 cm3 (B) 600 cm3 (C) 400 cm3 (D) 500 cm3? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 200cm3 of NH3 completely decomposed to N2 and H2 volume of the reaction mixture under same condition temperature and pressure would be (A) 200 cm3 (B) 600 cm3 (C) 400 cm3 (D) 500 cm3? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 200cm3 of NH3 completely decomposed to N2 and H2 volume of the reaction mixture under same condition temperature and pressure would be (A) 200 cm3 (B) 600 cm3 (C) 400 cm3 (D) 500 cm3?.
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