JEE Exam > JEE Questions > A linear harmonic oscillator of force constan...
Start Learning for Free
A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.
Its
Its
- a)maximum potential energy is 100 J
- b)maximum kinetic energy is 100 J
- c)maximum potential energy is 160 J
- d)maximum potential energy is zero
Correct answer is option 'B,C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A linear harmonic oscillator of force constant 2 × 106 N/m and a...
The total energy of the oscillator
As total mechanical energy = 160 J
The P.E. at equilibrium position is not zero.
P.E. at mean position = (160 – 100) J = 60 J
∴ Max P.E. = (100 + 60 ) J = 160 J.
The P.E. at equilibrium position is not zero.
P.E. at mean position = (160 – 100) J = 60 J
∴ Max P.E. = (100 + 60 ) J = 160 J.
Most Upvoted Answer
A linear harmonic oscillator of force constant 2 × 106 N/m and a...
The equation of motion for a linear harmonic oscillator is given by:
m(d^2x/dt^2) + kx = 0
where m is the mass of the oscillator, x is the displacement from equilibrium, t is time, and k is the force constant.
In this case, the force constant is 2. Therefore, the equation of motion becomes:
m(d^2x/dt^2) + 2x = 0
m(d^2x/dt^2) + kx = 0
where m is the mass of the oscillator, x is the displacement from equilibrium, t is time, and k is the force constant.
In this case, the force constant is 2. Therefore, the equation of motion becomes:
m(d^2x/dt^2) + 2x = 0
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer?
Question Description
A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer?.
A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer?.
Solutions for A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer?, a detailed solution for A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer? has been provided alongside types of A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A linear harmonic oscillator of force constant 2 × 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J.Itsa)maximum potential energy is 100 Jb)maximum kinetic energy is 100 Jc)maximum potential energy is 160 Jd)maximum potential energy is zeroCorrect answer is option 'B,C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup