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A rectangular coil of 20 turns and area of crosssection 25 sq. cm has a resistance of 100Ω. If amagnetic field which is perpendicular to the planeof coil changes at a rate of 1000 tesla per second,the current in the coil is [1992]
  • a)
    1 A
  • b)
    50 A
  • c)
    0.5 A
  • d)
    5 A
Correct answer is option 'C'. Can you explain this answer?
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A rectangular coil of 20 turns and area of crosssection 25 sq. cm has ...
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A rectangular coil of 20 turns and area of crosssection 25 sq. cm has ...
I= EMF/R nA db/dt/R 20×.0025×1000/100 =0.5A
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Community Answer
A rectangular coil of 20 turns and area of crosssection 25 sq. cm has ...
To find the resistance of the coil, we can use the formula:

Resistance = (resistivity * length) / (cross-sectional area)

Given that the resistance is 100 and the cross-sectional area is 25 sq. cm, we can rearrange the formula to solve for the resistivity:

Resistivity = (Resistance * cross-sectional area) / length

Since the length is not given, we cannot calculate the resistivity without additional information.
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A rectangular coil of 20 turns and area of crosssection 25 sq. cm has a resistance of 100Ω. If amagnetic field which is perpendicular to the planeof coil changes at a rate of 1000 tesla per second,the current in the coil is [1992]a)1 Ab)50 Ac)0.5 Ad)5 ACorrect answer is option 'C'. Can you explain this answer?
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