A closed planar wire loop of area A and arbitrary shape is placed in a uniform magnetic field of magnitude B, with its plane perpendicular to magnetic field. The resistance of the wire loop is R. The loop is now turned upside down by 180anddeg; so that its plane again becomes perpendicular to the magnetic field. The total charge that must have flowen through the wire ring in the process isa)andlt; AB/Rb)= AB/Rc)= 2AB/Rd)NoneCorrect answer is option 'C'. Can you explain this answer?

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A closed planar wire loop of area A and arbitrary shape is placed in a uniform magnetic field of magnitude B, with its plane perpendicular to magnetic field. The resistance of the wire loop is R. The loop is now turned upside down by 180° so that its plane again becomes perpendicular to the magnetic field. The total charge that must have flowen through the wire ring in the process is

a)
< AB/R
b)
= AB/R
c)
= 2AB/R
d)
None

Correct answer is option 'C'. Can you explain this answer?

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Test: Electromagnetic Induction - 2

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A closed planar wire loop of area A and arbitrary shape is placed in a...

Induced emf= d(flux)/dt=R[dq/dt]
⇒Δq= Δ(flux)/R=2BA/R

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A closed planar wire loop of area A and arbitrary shape is placed in a...

Degrees, so that its plane is still perpendicular to the magnetic field. What happens to the magnitude of the magnetic flux through the loop?

When the loop is turned upside down, the magnitude of the magnetic flux through the loop remains the same. This is because the magnetic flux is defined as the product of the magnetic field strength and the area through which it passes, and both the magnetic field strength and the area remain unchanged when the loop is flipped.

Mathematically, the magnetic flux through a loop is given by the equation:

Φ = B * A * cos(θ)

Where Φ is the magnetic flux, B is the magnetic field strength, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the loop.

Since the loop is initially perpendicular to the magnetic field, θ = 0 and cos(θ) = 1. When the loop is flipped, the angle between the magnetic field and the normal to the loop becomes 180 degrees, which means θ = π and cos(θ) = -1.

However, since the area of the loop remains the same and the magnetic field strength remains the same, the magnitude of the magnetic flux remains unchanged.

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A closed planar wire loop of area A and arbitrary shape is placed in a uniform magnetic field of magnitude B, with its plane perpendicular to magnetic field. The resistance of the wire loop is R. The loop is now turned upside down by 180° so that its plane again becomes perpendicular to the magnetic field. The total charge that must have flowen through the wire ring in the process isa)< AB/Rb)= AB/Rc)= 2AB/Rd)NoneCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A closed planar wire loop of area A and arbitrary shape is placed in a uniform magnetic field of magnitude B, with its plane perpendicular to magnetic field. The resistance of the wire loop is R. The loop is now turned upside down by 180° so that its plane again becomes perpendicular to the magnetic field. The total charge that must have flowen through the wire ring in the process isa)< AB/Rb)= AB/Rc)= 2AB/Rd)NoneCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A closed planar wire loop of area A and arbitrary shape is placed in a uniform magnetic field of magnitude B, with its plane perpendicular to magnetic field. The resistance of the wire loop is R. The loop is now turned upside down by 180° so that its plane again becomes perpendicular to the magnetic field. The total charge that must have flowen through the wire ring in the process isa)< AB/Rb)= AB/Rc)= 2AB/Rd)NoneCorrect answer is option 'C'. Can you explain this answer?.

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