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A conductor of length 0.4 m is moving with aspeed of 7 m/s perpendicular to a magnetic fieldof intensity 0.9 Wb/m2. The induced e.m.f.across the conductor is [1995]
- a)1.26 V
- b)2.52 V
- c)5.04 V
- d)25.2 V
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A conductor of length 0.4 m is moving with aspeed of 7 m/s perpendicul...
Length of conductor (l) = 0.4 m; Speed (v) = 7 m/s and magnetic field (B) = 0.9 Wb/ m2.
Induced e.m.f. (V) = Blv sin θ = 0.9 × 0.4 × 7
× sin 90º = 2.52 V.
Induced e.m.f. (V) = Blv sin θ = 0.9 × 0.4 × 7
× sin 90º = 2.52 V.
Most Upvoted Answer
A conductor of length 0.4 m is moving with aspeed of 7 m/s perpendicul...
Given:
Length of conductor (l) = 0.4 m
Speed of conductor (v) = 7 m/s
Magnetic field intensity (B) = 0.9 Wb/m²
To find:
Induced e.m.f across the conductor
Formula:
The induced e.m.f (E) can be calculated using the formula:
E = B * l * v
Calculation:
Substituting the given values into the formula, we have:
E = (0.9 Wb/m²) * (0.4 m) * (7 m/s)
Simplifying the above expression, we get:
E = 0.9 * 0.4 * 7 Wb
E = 2.52 V
Therefore, the induced e.m.f across the conductor is 2.52 V.
Explanation:
- The induced e.m.f across a conductor moving perpendicular to a magnetic field can be calculated using the formula E = B * l * v, where E is the induced e.m.f, B is the magnetic field intensity, l is the length of the conductor, and v is the speed of the conductor.
- In this case, the length of the conductor is given as 0.4 m, the speed of the conductor is given as 7 m/s, and the magnetic field intensity is given as 0.9 Wb/m².
- Substituting these values into the formula, we can calculate the induced e.m.f.
- By multiplying the magnetic field intensity, length of the conductor, and speed of the conductor, we find that the induced e.m.f is 2.52 V.
- Therefore, the correct answer is option B, 2.52 V.
Length of conductor (l) = 0.4 m
Speed of conductor (v) = 7 m/s
Magnetic field intensity (B) = 0.9 Wb/m²
To find:
Induced e.m.f across the conductor
Formula:
The induced e.m.f (E) can be calculated using the formula:
E = B * l * v
Calculation:
Substituting the given values into the formula, we have:
E = (0.9 Wb/m²) * (0.4 m) * (7 m/s)
Simplifying the above expression, we get:
E = 0.9 * 0.4 * 7 Wb
E = 2.52 V
Therefore, the induced e.m.f across the conductor is 2.52 V.
Explanation:
- The induced e.m.f across a conductor moving perpendicular to a magnetic field can be calculated using the formula E = B * l * v, where E is the induced e.m.f, B is the magnetic field intensity, l is the length of the conductor, and v is the speed of the conductor.
- In this case, the length of the conductor is given as 0.4 m, the speed of the conductor is given as 7 m/s, and the magnetic field intensity is given as 0.9 Wb/m².
- Substituting these values into the formula, we can calculate the induced e.m.f.
- By multiplying the magnetic field intensity, length of the conductor, and speed of the conductor, we find that the induced e.m.f is 2.52 V.
- Therefore, the correct answer is option B, 2.52 V.
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A conductor of length 0.4 m is moving with aspeed of 7 m/s perpendicular to a magnetic fieldof intensity 0.9 Wb/m2. The induced e.m.f.across the conductor is [1995]a)1.26 Vb)2.52 Vc)5.04 Vd)25.2 VCorrect answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A conductor of length 0.4 m is moving with aspeed of 7 m/s perpendicular to a magnetic fieldof intensity 0.9 Wb/m2. The induced e.m.f.across the conductor is [1995]a)1.26 Vb)2.52 Vc)5.04 Vd)25.2 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A conductor of length 0.4 m is moving with aspeed of 7 m/s perpendicular to a magnetic fieldof intensity 0.9 Wb/m2. The induced e.m.f.across the conductor is [1995]a)1.26 Vb)2.52 Vc)5.04 Vd)25.2 VCorrect answer is option 'B'. Can you explain this answer?.
A conductor of length 0.4 m is moving with aspeed of 7 m/s perpendicular to a magnetic fieldof intensity 0.9 Wb/m2. The induced e.m.f.across the conductor is [1995]a)1.26 Vb)2.52 Vc)5.04 Vd)25.2 VCorrect answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A conductor of length 0.4 m is moving with aspeed of 7 m/s perpendicular to a magnetic fieldof intensity 0.9 Wb/m2. The induced e.m.f.across the conductor is [1995]a)1.26 Vb)2.52 Vc)5.04 Vd)25.2 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A conductor of length 0.4 m is moving with aspeed of 7 m/s perpendicular to a magnetic fieldof intensity 0.9 Wb/m2. The induced e.m.f.across the conductor is [1995]a)1.26 Vb)2.52 Vc)5.04 Vd)25.2 VCorrect answer is option 'B'. Can you explain this answer?.
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