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Sum of two numbers x, y = 1050. What is the maximum value of the HCF between x and y?
  • a)
    350
  • b)
    700
  • c)
    1050
  • d)
    525
  • e)
    900
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Sum of two numbers x, y = 1050. What is the maximum value of the HCF b...
x = 525 and y = 525 works best.
If the question states x, y have to be distinct, then the best solution would be x = 350, y = 700, HCF = 350.
So the HCF is 525.
The question is "What is the maximum value of the HCF between x and y?"
Hence the answer is "525"
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Most Upvoted Answer
Sum of two numbers x, y = 1050. What is the maximum value of the HCF b...
Solution:

To find the maximum value of the HCF between x and y, we need to find the highest common factor of the two numbers.

Let's assume that x and y have a common factor d, where d is the HCF of x and y. Then we can write:

x = a * d
y = b * d

Where a and b are two integers. Since x + y = 1050, we can substitute the above equations and get:

a * d + b * d = 1050
d * (a + b) = 1050

Since d is a factor of both x and y, it must also be a factor of 1050. Therefore, we need to find the maximum factor of 1050 that can divide both x and y.

The prime factorization of 1050 is:

1050 = 2 * 3 * 5 * 7 * 5

To find the maximum factor of 1050 that can divide x and y, we need to find the highest value of d such that d is a factor of 1050 and a + b = 1050 / d.

Let's start with the highest factor of 1050, which is 1050 itself. If d = 1050, then a + b = 1, which is not possible since a and b are integers. Therefore, we need to try the next highest factor of 1050, which is 525.

If d = 525, then a + b = 2. The only possible values of a and b that satisfy this equation are a = 1 and b = 1. Therefore, the maximum value of the HCF of x and y is:

HCF(x, y) = d = 525

Therefore, the correct answer is option D, 525.
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Sum of two numbers x, y = 1050. What is the maximum value of the HCF between x and y?a)350b)700c)1050d)525e)900Correct answer is option 'D'. Can you explain this answer?
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