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A person borrowed rs.8000 at a certain rate of interest for 2 years and then rs.10000 at 1% lower than the first.In all he paid rs.2500 as interst in 3 years.Find the two rates at which he borrowed the amount. (b) In what time will a sum of money double itself at 5% Compound interest payable half yearly ?
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A person borrowed rs.8000 at a certain rate of interest for 2 years an...
Calculation of Interest Rates

  • Let the first rate of interest be x%

  • Then, the second rate of interest will be (x-1)%

  • Interest on first loan = (8000*x*2)/100 = 160x

  • Interest on second loan = (10000*(x-1)*1)/100 = 100(x-1)

  • Total interest paid in 3 years = 2500

  • Therefore, total interest paid in first 2 years = 160x + 100(x-1) = 260x - 100

  • Interest paid in the third year = total interest - interest paid in first 2 years = 2500 - (260x - 100) = 2500 - 260x + 100 = 2400 - 260x

  • Interest on first loan in third year = (8000*x*1)/100 = 80x

  • Interest on second loan in third year = (10000*(x-1)*2)/100 = 200(x-1)

  • Therefore, 80x + 200(x-1) = 2400 - 260x

  • Solving the equation, we get x = 12 and (x-1) = 11

  • Therefore, the first rate of interest is 12% and the second rate of interest is 11%



Calculation of Time for Doubling of Money

  • Let the principal amount be P

  • Compound interest rate = 5% per annum

  • Interest rate per half year = 2.5%

  • Let the time taken to double the money be t years

  • Amount after t years = P*(1 + 2.5/100)^(2t)

  • Amount after doubling = 2P

  • Therefore, 2P = P*(1 + 2.5/100)^(2t)

  • Simplifying the equation, we get (1 + 2.5/100)^(2t) = 2

  • Taking log on both sides, we get 2t*log(1.025) = log(2)

  • Therefore, t = log(2)/(2*log(1.025)) = 13.86 years (approx)

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A person borrowed rs.8000 at a certain rate of interest for 2 years and then rs.10000 at 1% lower than the first.In all he paid rs.2500 as interst in 3 years.Find the two rates at which he borrowed the amount. (b) In what time will a sum of money double itself at 5% Compound interest payable half yearly ?
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