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The magnetic field between the Horizontal poles of an electromagnet is uniform at any time, but its magnitude is increasing at the rate of 0.020T/s.The area of a horizontal conducting loop in the magnetic field is 120cm2, and the total circuit resistance, including the meter, is 5Ω. Induced emf and the induced current in the circuit are
  • a)
    0.18 mV,0.048 mA
  • b)
    0.22 mV,0.048 mA
  • c)
    0.20 mV,0.048 mA
  • d)
    0.24 mV,0.048 mA
Correct answer is option 'D'. Can you explain this answer?
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The magnetic field between the Horizontal poles of an electromagnet is...
Explanation:
e = Rate of change of magnetic field x area
 
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The magnetic field between the Horizontal poles of an electromagnet is...
Magnetic Field
- The magnetic field between the horizontal poles of an electromagnet is uniform at any time.
- The magnitude of the magnetic field is increasing at a rate of 0.020 T/s.

Conducting Loop
- The area of the horizontal conducting loop in the magnetic field is 120 cm^2.
- The total circuit resistance, including the meter, is 5 Ω.

Induced EMF
- The induced EMF can be calculated using Faraday's law of electromagnetic induction.
- Faraday's law states that the induced EMF is equal to the rate of change of magnetic flux through the loop.
- The magnetic flux through the loop can be calculated by multiplying the magnetic field strength by the area of the loop.
- The rate of change of magnetic flux is equal to the rate of change of the magnetic field strength multiplied by the area of the loop.
- Substituting the given values, the rate of change of magnetic flux is (0.020 T/s) * (120 cm^2) = 2.4 T cm^2/s.
- To convert the magnetic flux to Weber (Wb), divide by 10,000: 2.4 T cm^2/s / 10,000 = 0.00024 Wb/s.
- Therefore, the induced EMF is 0.00024 V/s or 0.24 mV/s.

Induced Current
- The induced current can be calculated using Ohm's law, which states that the current is equal to the voltage divided by the resistance.
- Substituting the given values, the induced current is (0.24 mV/s) / (5 Ω) = 0.048 mA.

Conclusion
- The induced EMF in the circuit is 0.24 mV and the induced current is 0.048 mA.
- Therefore, the correct answer is option 'D', 0.24 mV, 0.048 mA.
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The magnetic field between the Horizontal poles of an electromagnet is uniform at any time, but its magnitude is increasing at the rate of 0.020T/s.The area of a horizontal conducting loop in the magnetic field is 120cm2, and the total circuit resistance, including the meter, is5Ω. Induced emf and the induced current in the circuit area)0.18 mV,0.048 mAb)0.22 mV,0.048 mAc)0.20 mV,0.048 mAd)0.24 mV,0.048 mACorrect answer is option 'D'. Can you explain this answer?
Question Description
The magnetic field between the Horizontal poles of an electromagnet is uniform at any time, but its magnitude is increasing at the rate of 0.020T/s.The area of a horizontal conducting loop in the magnetic field is 120cm2, and the total circuit resistance, including the meter, is5Ω. Induced emf and the induced current in the circuit area)0.18 mV,0.048 mAb)0.22 mV,0.048 mAc)0.20 mV,0.048 mAd)0.24 mV,0.048 mACorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The magnetic field between the Horizontal poles of an electromagnet is uniform at any time, but its magnitude is increasing at the rate of 0.020T/s.The area of a horizontal conducting loop in the magnetic field is 120cm2, and the total circuit resistance, including the meter, is5Ω. Induced emf and the induced current in the circuit area)0.18 mV,0.048 mAb)0.22 mV,0.048 mAc)0.20 mV,0.048 mAd)0.24 mV,0.048 mACorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnetic field between the Horizontal poles of an electromagnet is uniform at any time, but its magnitude is increasing at the rate of 0.020T/s.The area of a horizontal conducting loop in the magnetic field is 120cm2, and the total circuit resistance, including the meter, is5Ω. Induced emf and the induced current in the circuit area)0.18 mV,0.048 mAb)0.22 mV,0.048 mAc)0.20 mV,0.048 mAd)0.24 mV,0.048 mACorrect answer is option 'D'. Can you explain this answer?.
Solutions for The magnetic field between the Horizontal poles of an electromagnet is uniform at any time, but its magnitude is increasing at the rate of 0.020T/s.The area of a horizontal conducting loop in the magnetic field is 120cm2, and the total circuit resistance, including the meter, is5Ω. Induced emf and the induced current in the circuit area)0.18 mV,0.048 mAb)0.22 mV,0.048 mAc)0.20 mV,0.048 mAd)0.24 mV,0.048 mACorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
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