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The magnetic field between the Horizontal poles of an electromagnet in is uniform at any time, but its magnitude is increasing at the rate of 0.020 T/s.The area of a loop made of perfect insulating material is 120cm2.This loop is kept horizontally in the magnetic field. Induced emf and the induced current in the circuit are
  • a)
    0.54 mV,zero
  • b)
    0.84 mV,zero
  • c)
    0.24 mV,zero
  • d)
    0.14 mV,zero
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The magnetic field between the Horizontal poles of an electromagnet in...
e = Rate of change of magnetic field x area
 
=0.02×120×10−4=0.24mV
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Most Upvoted Answer
The magnetic field between the Horizontal poles of an electromagnet in...
Given:
Rate of increase of magnetic field, dB/dt = 0.020 T/s
Area of the loop, A = 120 cm^2 = 0.012 m^2

To find:
Induced EMF and induced current in the circuit.

Solution:
We know that the induced EMF in a loop is given by the formula:
EMF = - dΦ/dt
where Φ is the magnetic flux passing through the loop.

Magnetic flux, Φ = BA
where B is the magnetic field strength and A is the area of the loop.

So, EMF = - d/dt (BA)

Differentiating both sides with respect to time t, we get:
EMF = - A dB/dt

Substituting the given values, we get:
EMF = - 0.012 x 0.020 = -0.00024 V = -0.24 mV (negative sign indicates that the direction of the induced current will be opposite to the direction of the change in magnetic field)

So, the induced EMF in the circuit is 0.24 mV.

Now, we know that the induced current in the circuit is given by Ohm's law:
I = EMF/R
where R is the resistance of the circuit.

As the loop is made of perfect insulating material, the resistance of the circuit is infinity, i.e., R = ∞. Therefore, the induced current in the circuit is zero.

Therefore, the correct option is (c) 0.24 mV, zero.
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The magnetic field between the Horizontal poles of an electromagnet in is uniform at any time, but its magnitude is increasing at the rate of 0.020 T/s.The area of a loop made of perfect insulating material is 120cm2.This loop is kept horizontally in the magnetic field. Induced emf and the induced current in the circuit area)0.54 mV,zerob)0.84 mV,zeroc)0.24 mV,zerod)0.14 mV,zeroCorrect answer is option 'C'. Can you explain this answer?
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The magnetic field between the Horizontal poles of an electromagnet in is uniform at any time, but its magnitude is increasing at the rate of 0.020 T/s.The area of a loop made of perfect insulating material is 120cm2.This loop is kept horizontally in the magnetic field. Induced emf and the induced current in the circuit area)0.54 mV,zerob)0.84 mV,zeroc)0.24 mV,zerod)0.14 mV,zeroCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The magnetic field between the Horizontal poles of an electromagnet in is uniform at any time, but its magnitude is increasing at the rate of 0.020 T/s.The area of a loop made of perfect insulating material is 120cm2.This loop is kept horizontally in the magnetic field. Induced emf and the induced current in the circuit area)0.54 mV,zerob)0.84 mV,zeroc)0.24 mV,zerod)0.14 mV,zeroCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnetic field between the Horizontal poles of an electromagnet in is uniform at any time, but its magnitude is increasing at the rate of 0.020 T/s.The area of a loop made of perfect insulating material is 120cm2.This loop is kept horizontally in the magnetic field. Induced emf and the induced current in the circuit area)0.54 mV,zerob)0.84 mV,zeroc)0.24 mV,zerod)0.14 mV,zeroCorrect answer is option 'C'. Can you explain this answer?.
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