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Two coins are tossed once ,where E :no tail appears , F : no head appers. Find P(E/F).
- a)0
- b)0.24
- c)0.22
- d)0.25
Correct answer is option 'A'. Can you explain this answer?
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Two coins are tossed once ,where E :no tail appears , F : no head appe...
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Two coins are tossed once ,where E :no tail appears , F : no head appe...
Calculation of P(E/F)
Understanding the Events E and F
Event E represents the case when no tail appears after two coin tosses. This means both outcomes are heads. Event F represents the case when no head appears after two coin tosses. This means both outcomes are tails.
Finding the Intersection of E and F
Since both E and F cannot happen simultaneously (both heads and both tails cannot occur at the same time), the intersection of E and F is an empty set. Therefore, P(E∩F) = 0.
Calculating P(E/F)
The conditional probability P(E/F) is defined as the probability of event E occurring given that event F has already occurred. In this case, since the intersection of E and F is empty (P(E∩F) = 0), we have P(E/F) = P(E∩F) / P(F) = 0 / P(F) = 0, as the denominator P(F) is not equal to 0.
Therefore, the correct answer is option 'A' (0) as the conditional probability P(E/F) in this scenario is 0.
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