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A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical.About the point of suspension:
- a)angular momentum is conserved.
- b)angular momentum changes in magnitude but not in direction.
- c)angular momentum changes in direction but not in magnitude.
- d)angular momentum changes both in direction and magnitude.
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A bob of mass m attached to an inextensible string of length l is susp...
Option c is correct since angular momentum= m×r×omega is a constant because m,l and magnitude of omega isn't changed . but angular speed being vector it's direction changes .so it would be right to say as option c...
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A bob of mass m attached to an inextensible string of length l is susp...
The angular speed of the bob, ω, is related to the linear speed, v, of the bob by the equation v = ω * r, where r is the radius of the circular path. In this case, the radius is equal to the length of the string, l.
The centripetal force, Fc, required to keep the bob moving in a circular path is given by the equation Fc = m * a, where m is the mass of the bob and a is the centripetal acceleration.
The centripetal acceleration, a, is related to the angular speed, ω, by the equation a = ω^2 * r.
Combining these equations, we can find an expression for the centripetal force:
Fc = m * a
Fc = m * (ω^2 * r)
Fc = m * (ω^2 * l)
In this case, the centripetal force is provided by the tension in the string, T. So, we can rewrite the equation as:
T = m * (ω^2 * l)
This equation relates the tension in the string to the mass of the bob, the length of the string, and the angular speed of the bob.
The centripetal force, Fc, required to keep the bob moving in a circular path is given by the equation Fc = m * a, where m is the mass of the bob and a is the centripetal acceleration.
The centripetal acceleration, a, is related to the angular speed, ω, by the equation a = ω^2 * r.
Combining these equations, we can find an expression for the centripetal force:
Fc = m * a
Fc = m * (ω^2 * r)
Fc = m * (ω^2 * l)
In this case, the centripetal force is provided by the tension in the string, T. So, we can rewrite the equation as:
T = m * (ω^2 * l)
This equation relates the tension in the string to the mass of the bob, the length of the string, and the angular speed of the bob.
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A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical.About the point of suspension:a)angular momentum is conserved.b)angular momentum changes in magnitude but not in direction.c)angular momentum changes in direction but not in magnitude.d)angular momentum changes both in direction and magnitude.Correct answer is option 'C'. Can you explain this answer?
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A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical.About the point of suspension:a)angular momentum is conserved.b)angular momentum changes in magnitude but not in direction.c)angular momentum changes in direction but not in magnitude.d)angular momentum changes both in direction and magnitude.Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical.About the point of suspension:a)angular momentum is conserved.b)angular momentum changes in magnitude but not in direction.c)angular momentum changes in direction but not in magnitude.d)angular momentum changes both in direction and magnitude.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical.About the point of suspension:a)angular momentum is conserved.b)angular momentum changes in magnitude but not in direction.c)angular momentum changes in direction but not in magnitude.d)angular momentum changes both in direction and magnitude.Correct answer is option 'C'. Can you explain this answer?.
A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical.About the point of suspension:a)angular momentum is conserved.b)angular momentum changes in magnitude but not in direction.c)angular momentum changes in direction but not in magnitude.d)angular momentum changes both in direction and magnitude.Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical.About the point of suspension:a)angular momentum is conserved.b)angular momentum changes in magnitude but not in direction.c)angular momentum changes in direction but not in magnitude.d)angular momentum changes both in direction and magnitude.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical.About the point of suspension:a)angular momentum is conserved.b)angular momentum changes in magnitude but not in direction.c)angular momentum changes in direction but not in magnitude.d)angular momentum changes both in direction and magnitude.Correct answer is option 'C'. Can you explain this answer?.
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ample number of questions to practice A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle with an angular speed ω rad/s about the vertical.About the point of suspension:a)angular momentum is conserved.b)angular momentum changes in magnitude but not in direction.c)angular momentum changes in direction but not in magnitude.d)angular momentum changes both in direction and magnitude.Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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