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The conditional probability of an event E’s complement E’, given the occurrence of the event F
  • a)
    P (E′|F) = 1
  • b)
    P (E′|F) = 1 – P (E|F)
  • c)
    P (E′|F) = – 1 + P (E|F)
  • d)
    P (E′|F) = P (E|F)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The conditional probability of an event E’s complement E’,...
As the total probability of an event is always 1 . therefore , P (E′|F) = 1 – P (E|F).
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The conditional probability of an event E’s complement E’,...
Conditional Probability of Event E's complement given the occurrence of Event F
The conditional probability of an event E's complement E, given the occurrence of the event F, can be calculated using the formula:

P(E' | F) = 1 - P(E | F)

Explanation:
- The complement of event E, denoted as E', represents all outcomes that are not in E.
- The conditional probability of E's complement given F is equal to 1 minus the conditional probability of E given F.
- This formula holds true because the sum of the probabilities of E and E' given F is equal to 1, as they are mutually exclusive and exhaustive events.
Therefore, the correct answer is option 'B': P(E' | F) = 1 - P(E | F).
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The conditional probability of an event E’s complement E’, given the occurrence of the event Fa)P (E′|F) = 1b)P (E′|F) = 1 – P (E|F)c)P (E′|F) = – 1 + P (E|F)d)P (E′|F) = P (E|F)Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The conditional probability of an event E’s complement E’, given the occurrence of the event Fa)P (E′|F) = 1b)P (E′|F) = 1 – P (E|F)c)P (E′|F) = – 1 + P (E|F)d)P (E′|F) = P (E|F)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The conditional probability of an event E’s complement E’, given the occurrence of the event Fa)P (E′|F) = 1b)P (E′|F) = 1 – P (E|F)c)P (E′|F) = – 1 + P (E|F)d)P (E′|F) = P (E|F)Correct answer is option 'B'. Can you explain this answer?.
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