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In a thin cylinder subjected to internal pressure, if lognitudinal stress is 30 N/mm2, circumferential stress is _________
  • a)
    15 N/mm2
  • b)
    30 N/mm2
  • c)
    60 N/mm2
  • d)
    90 N/mm2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In a thin cylinder subjected to internal pressure, if lognitudinal str...
In thin cylinder longitudinal stress 
Circumferential / hoop stress,
∴ Hoop stress σn = 2σl 
= 2 × 30
= 60 N/mm2
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Most Upvoted Answer
In a thin cylinder subjected to internal pressure, if lognitudinal str...
The stress in a thin cylinder subjected to internal pressure can be determined using the equations for longitudinal and circumferential stress.

Longitudinal stress (σl) is the stress acting parallel to the length of the cylinder, while circumferential stress (σc) is the stress acting perpendicular to the length of the cylinder.

The relationship between these two stresses can be given by the formula:

σl = σc / 2

Given that the longitudinal stress is 30 N/mm^2, we can substitute this value into the equation to solve for the circumferential stress.

σl = σc / 2
30 N/mm^2 = σc / 2

To find the circumferential stress, we can rearrange the equation:

σc = 2 * σl
σc = 2 * 30 N/mm^2
σc = 60 N/mm^2

Therefore, the correct answer is option C) 60 N/mm^2.
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In a thin cylinder subjected to internal pressure, if lognitudinal stress is 30 N/mm2, circumferential stress is _________a)15 N/mm2b)30 N/mm2c)60 N/mm2d)90 N/mm2Correct answer is option 'C'. Can you explain this answer?
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