JEE Exam > JEE Questions > A car is moving in a circular horizontal trac...
Start Learning for Free
A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track is
- a)zero
- b)30°
- c)45°
- d)60°
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A car is moving in a circular horizontal track of radius 10 m with a c...
When the car is moving in a circular horizontal track of radius 10 m with a constant speed, then the bob is also undergoing a circular motion. The bob is under the influence of two forces.
(i) T (tension in the rod)
(ii) mg (weight of the bob)
Resolving tension, we get
Tcosθ = mg ... (i)
And Tsinθ = mv2/r ... (ii)
(Here T sin θ is producing the necessary centripetal force for circular motion)
Dividing (ii) by (i), we get
Most Upvoted Answer
A car is moving in a circular horizontal track of radius 10 m with a c...
C) 45d) 60
The correct answer is c) 45 degrees.
To find the angle made by the rod with the track, we can use the concept of centripetal force.
The centripetal force is the force that keeps an object moving in a circular path. It is directed towards the center of the circle.
In this case, the centripetal force is provided by the tension in the rod. The tension in the rod can be resolved into two components: one along the direction of motion of the car, and the other perpendicular to it.
Since the car is moving with a constant speed in a circular path, the net force acting on it must be zero. This means that the perpendicular component of the tension must be equal in magnitude and opposite in direction to the gravitational force acting on the bob.
The gravitational force acting on the bob is given by the equation F = mg, where m is the mass of the bob and g is the acceleration due to gravity.
The tension in the rod can be calculated using the equation T = mg + ma, where a is the centripetal acceleration of the car.
The centripetal acceleration can be calculated using the equation a = v^2/r, where v is the speed of the car and r is the radius of the circular track.
Substituting the given values, we get a = (10 m/s)^2 / 10 m = 10 m/s^2.
Substituting the values of m, g, and a into the equation for tension, we get T = m(10 m/s^2) + mg.
Since the angle made by the rod with the track is the angle between the tension and the vertical direction, we can use trigonometry to find this angle.
The cosine of the angle is given by the equation cos(theta) = (mg)/T.
Substituting the values of m, g, and T into this equation, we get cos(theta) = (1 kg)(10 m/s^2)/(10 N) = 1/1 = 1.
Therefore, the angle made by the rod with the track is theta = cos^(-1)(1) = 45 degrees.
The correct answer is c) 45 degrees.
To find the angle made by the rod with the track, we can use the concept of centripetal force.
The centripetal force is the force that keeps an object moving in a circular path. It is directed towards the center of the circle.
In this case, the centripetal force is provided by the tension in the rod. The tension in the rod can be resolved into two components: one along the direction of motion of the car, and the other perpendicular to it.
Since the car is moving with a constant speed in a circular path, the net force acting on it must be zero. This means that the perpendicular component of the tension must be equal in magnitude and opposite in direction to the gravitational force acting on the bob.
The gravitational force acting on the bob is given by the equation F = mg, where m is the mass of the bob and g is the acceleration due to gravity.
The tension in the rod can be calculated using the equation T = mg + ma, where a is the centripetal acceleration of the car.
The centripetal acceleration can be calculated using the equation a = v^2/r, where v is the speed of the car and r is the radius of the circular track.
Substituting the given values, we get a = (10 m/s)^2 / 10 m = 10 m/s^2.
Substituting the values of m, g, and a into the equation for tension, we get T = m(10 m/s^2) + mg.
Since the angle made by the rod with the track is the angle between the tension and the vertical direction, we can use trigonometry to find this angle.
The cosine of the angle is given by the equation cos(theta) = (mg)/T.
Substituting the values of m, g, and T into this equation, we get cos(theta) = (1 kg)(10 m/s^2)/(10 N) = 1/1 = 1.
Therefore, the angle made by the rod with the track is theta = cos^(-1)(1) = 45 degrees.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer?
Question Description
A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer?.
A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer?.
Solutions for A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1.00 m. The angle made by the rod with track isa)zerob)30°c)45°d)60°Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup