The sum of an exterior angle and an interior angle of a polygon = 180^{o}. The sum of all the exterior angles of a polygon = 360^{o}. From the question stem: sum of all interior angles of the given polygon = 1440^{o}. Therefore, sum of all the interior and all exterior angles of the polygon = 1440 + 360 = 1800^{o}.
The sum of an exterior angle and an interior angle of a polygon = 180o.The sum of all the exterior angles of a polygon = 360o.From the question stem: sum of all interior angles of the given polygon = 1440o.Therefore, sum of all the interior and all exterior angles of the polygon = 1440 + 360 = 1800o.
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The sum of an exterior angle and an interior angle of a polygon = 180o.The sum of all the exterior angles of a polygon = 360o.From the question stem: sum of all interior angles of the given polygon = 1440o.Therefore, sum of all the interior and all exterior angles of the polygon = 1440 + 360 = 1800o.