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Comprehension Type
Direction (Q. Nos. 15-17) This section contains a paragraph, describing theory, experiments, data, etc.
Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).
Passage
A neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.
Q. 
 How many different stereoisomers exist for A ?
  • a)
    2
  • b)
    4
  • c)
    5
  • d)
    6
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Comprehension TypeDirection (Q. Nos. 15-17) This section contains a pa...
From the given information, it appears that A is an ester. Since, D on Tischenko reaction gives back A indicates that in ester, both acid and alcohol fragments (B and C respectively) has five carbon atoms each. Also, C is an alcohol which has a chiral carbon and no CH3CH(OH)— grouping (not giving iodoform). Controlled oxidation of C gives D, a carbonyl which is still chiral. Hence, D must be an aldehyde with a chiral carbon.

The above ester has two chiral carbons and no symmetry hence, four stereoisomers.
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Comprehension TypeDirection (Q. Nos. 15-17) This section contains a pa...
Understanding the number of stereoisomers for compound A:
Compound A(C10H20O2) can be resolved into enantiomers, which means it has chiral centers and exists as enantiomeric pairs.

Analysis of the given information:
- A on acid hydrolysis forms two enantiomeric compounds B and C.
- C on oxidation with CrO3/HCl/pyridine forms D.
- D on further treatment with aqueous (C2H5O)3 Al solution gives back compound A.

Determining the number of stereoisomers:
- Since A can be resolved into enantiomers, it means there are 2 possible enantiomeric forms for A.
- When A is hydrolyzed to B and C, both B and C are enantiomeric, adding 2 more stereoisomers.
- Compound D, formed from C, is still resolvable into enantiomers, so it adds 2 more stereoisomers.
- Therefore, the total number of stereoisomers for compound A is 2 (enantiomers of A) + 2 (enantiomers of B and C) + 2 (enantiomers of D) = 6.
Therefore, there are a total of 6 different stereoisomers for compound A.
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Comprehension TypeDirection (Q. Nos. 15-17) This section contains a paragraph, describing theory, experiments, data, etc.Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageA neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.How many different stereoisomers exist for A ?a)2b)4c)5d)6Correct answer is option 'B'. Can you explain this answer?
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Comprehension TypeDirection (Q. Nos. 15-17) This section contains a paragraph, describing theory, experiments, data, etc.Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageA neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.How many different stereoisomers exist for A ?a)2b)4c)5d)6Correct answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Comprehension TypeDirection (Q. Nos. 15-17) This section contains a paragraph, describing theory, experiments, data, etc.Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageA neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.How many different stereoisomers exist for A ?a)2b)4c)5d)6Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Comprehension TypeDirection (Q. Nos. 15-17) This section contains a paragraph, describing theory, experiments, data, etc.Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageA neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.How many different stereoisomers exist for A ?a)2b)4c)5d)6Correct answer is option 'B'. Can you explain this answer?.
Solutions for Comprehension TypeDirection (Q. Nos. 15-17) This section contains a paragraph, describing theory, experiments, data, etc.Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageA neutral organic compound A(C10H20O2) neither reduces Tollen’s reagent nor forms precipitate with 2, 4-dinitrophenyl hydrazine, but can be resolved into enantiomers. A on acid hydrolysis forms two compounds B and C, both are enantiomeric. C neither reduces Fehling’s solution nor forms iodoform with alkaline iodine solution. C on oxidation with CrO3/HCI /pyridineforms D which is still resolvable into enantiomers. D on further treatment with aqueous (C2H5O)3 Al solution gives back A.Q.How many different stereoisomers exist for A ?a)2b)4c)5d)6Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
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