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The magnitude of electric field strength E such that an electron placed in it would experience an electrical force equal to its weight, is given by
- a)mg
- b)mg/e
- c)mg/e2
- d)e/mg
Correct answer is option 'B'. Can you explain this answer?
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Explanation:
When an electron is placed in an electric field, it experiences a force given by:
F = qE
where F is the force experienced by the electron, q is the charge of the electron, and E is the electric field strength.
The weight of the electron is given by:
W = mg
where m is the mass of the electron and g is the acceleration due to gravity.
To find the magnitude of electric field strength E such that an electron placed in it would experience an electrical force equal to its weight, we can equate F and W:
F = W
qE = mg
E = mg/q
Since the charge of an electron is -e, where e is the elementary charge, we can substitute q = -e:
E = mg/(-e)
E = -mg/e
Therefore, the magnitude of electric field strength E such that an electron placed in it would experience an electrical force equal to its weight is given by:
E = mg/e
Hence, option B is the correct answer.
When an electron is placed in an electric field, it experiences a force given by:
F = qE
where F is the force experienced by the electron, q is the charge of the electron, and E is the electric field strength.
The weight of the electron is given by:
W = mg
where m is the mass of the electron and g is the acceleration due to gravity.
To find the magnitude of electric field strength E such that an electron placed in it would experience an electrical force equal to its weight, we can equate F and W:
F = W
qE = mg
E = mg/q
Since the charge of an electron is -e, where e is the elementary charge, we can substitute q = -e:
E = mg/(-e)
E = -mg/e
Therefore, the magnitude of electric field strength E such that an electron placed in it would experience an electrical force equal to its weight is given by:
E = mg/e
Hence, option B is the correct answer.
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The magnitude of electric field strength E such that an electron placed in it would experience an electrical force equal to its weight, is given bya)mgb)mg/ec)mg/e2d)e/mgCorrect answer is option 'B'. Can you explain this answer?
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