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X is smallest positive integer such that when it is divided by 7, 8 & 9 leaves remainder as 4,5 & 6 respectively find the remainder when x³ 2x²-x-3 is divided by 132. A)49 B)76 C)94 D)15 Correct answer is option D can you explain this answer?
Most Upvoted Answer
X is smallest positive integer such that when it is divided by 7, 8 & ...
To find the smallest positive integer that satisfies the given conditions, we need to find the least common multiple (LCM) of 7, 8, and 9.

Prime factorizing the numbers:
7 = 7
8 = 2^3
9 = 3^2

To find the LCM, we take the highest power of each prime factor that appears in the prime factorization of any of the numbers.

LCM = 2^3 * 3^2 * 7 = 168

Therefore, the smallest positive integer that satisfies the given conditions is 168.
Community Answer
X is smallest positive integer such that when it is divided by 7, 8 & ...
B)76
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X is smallest positive integer such that when it is divided by 7, 8 & 9 leaves remainder as 4,5 & 6 respectively find the remainder when x³ 2x²-x-3 is divided by 132. A)49 B)76 C)94 D)15 Correct answer is option D can you explain this answer?
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