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An engine working on Carnot cycle rejects 40% of absorbed heat from the source, while the sink temperature is maintained at 27°C, then what is the source temperature?
- a)750°C
- b)477°C
- c)203°C
- d)67.5°C
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
An engine working on Carnot cycle rejects 40% of absorbed heat from th...
Sink temperature = 27C = 27 + 273 = 300K
It is given that engine rejects 40% of absorbed heat from the source
It is given that engine rejects 40% of absorbed heat from the source
Most Upvoted Answer
An engine working on Carnot cycle rejects 40% of absorbed heat from th...
To find the source temperature in a Carnot cycle, we can use the Carnot efficiency formula, which is given by:
Efficiency = 1 - (T_sink / T_source)
Here, T_sink is the temperature of the sink (maintained at 27°C) and T_source is the temperature of the source (which we need to find).
Given that the engine rejects 40% of the absorbed heat, we can also say that the engine's efficiency is 60% (100% - 40%). So, we have:
Efficiency = 60% = 0.6
Now, let's solve the equation for T_source.
1 - (T_sink / T_source) = 0.6
We can rearrange the equation to isolate T_source:
(T_sink / T_source) = 1 - 0.6
(T_sink / T_source) = 0.4
T_sink = 27°C
(T_sink / T_source) = 0.4
T_source = T_sink / 0.4
T_source = 27°C / 0.4
T_source = 67.5°C
Therefore, the source temperature is 67.5°C.
Hence, the correct answer is option 'D'.
Efficiency = 1 - (T_sink / T_source)
Here, T_sink is the temperature of the sink (maintained at 27°C) and T_source is the temperature of the source (which we need to find).
Given that the engine rejects 40% of the absorbed heat, we can also say that the engine's efficiency is 60% (100% - 40%). So, we have:
Efficiency = 60% = 0.6
Now, let's solve the equation for T_source.
1 - (T_sink / T_source) = 0.6
We can rearrange the equation to isolate T_source:
(T_sink / T_source) = 1 - 0.6
(T_sink / T_source) = 0.4
T_sink = 27°C
(T_sink / T_source) = 0.4
T_source = T_sink / 0.4
T_source = 27°C / 0.4
T_source = 67.5°C
Therefore, the source temperature is 67.5°C.
Hence, the correct answer is option 'D'.
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An engine working on Carnot cycle rejects 40% of absorbed heat from the source, while the sink temperature is maintained at 27°C, then what is the source temperature?a)750°Cb)477°Cc)203°Cd)67.5°CCorrect answer is option 'B'. Can you explain this answer?
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