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Two Carnot engines A and B are connected in series between two thermal reservoirs maintained at 1000 K and 100 K respectively. Engine A receives 1680 KJ of heat from high temperature reservoir and rejects heat to the carnot engine B. Engine B takes in heat rejection by engine A and rejects heat to the low temperature reservoir. If engine A and B deliver equal amount of work, the efficiencies of A and B engines are
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Solution:

Given data:

- High temperature reservoir temperature (TH) = 1000 K
- Low temperature reservoir temperature (TL) = 100 K
- Heat received by engine A (Qin) = 1680 kJ
- Work output of engine A (WoutA) = Work output of engine B (WoutB)
- Efficiency of engine A (ηA) = ?
- Efficiency of engine B (ηB) = ?

To find:

- Efficiencies of engines A and B

Assumptions made:

- Both the engines operate on Carnot cycle

Formula used:

- Efficiency of Carnot cycle (η) = (TH – TL) / TH

Calculation:

- Efficiency of Carnot cycle for engine A (ηA) = (TH – TL) / TH = (1000 – 100) / 1000 = 0.9 or 90%
- As engine A rejects heat to engine B, the heat rejected by engine A (QoutA) = Qin – WoutA
- Heat input to engine B (QinB) = QoutA = Qin – WoutA
- Efficiency of Carnot cycle for engine B (ηB) = (TH – TL) / TL = (1000 – 100) / 100 = 9 or 900%
- As engine B rejects heat to the low temperature reservoir, the heat rejected by engine B (QoutB) = QinB – WoutB = QoutA – WoutB
- As WoutA = WoutB, QoutA – WoutB = QoutB
- Therefore, QoutA = 2 * WoutA
- From the first law of thermodynamics, QinB – QoutA = WoutA
- Substituting the values, QoutA = 2 * WoutA and QinB = QoutA – WoutB, we get WoutA = 840 kJ and WoutB = 840 kJ
- Efficiency of engine B (ηB) = WoutB / QinB = 840 / (QoutA – WoutB) = 840 / (2 * WoutA – WoutB) = 0.35 or 35%

Therefore, the efficiencies of engines A and B are:

- Efficiency of engine A (ηA) = 0.9 or 90%
- Efficiency of engine B (ηB) = 0.35 or 35%
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Two Carnot engines A and B are connected in series between two thermal reservoirs maintained at 1000 K and 100 K respectively. Engine A receives 1680 KJ of heat from high temperature reservoir and rejects heat to the carnot engine B. Engine B takes in heat rejection by engine A and rejects heat to the low temperature reservoir. If engine A and B deliver equal amount of work, the efficiencies of A and B engines are
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Two Carnot engines A and B are connected in series between two thermal reservoirs maintained at 1000 K and 100 K respectively. Engine A receives 1680 KJ of heat from high temperature reservoir and rejects heat to the carnot engine B. Engine B takes in heat rejection by engine A and rejects heat to the low temperature reservoir. If engine A and B deliver equal amount of work, the efficiencies of A and B engines are for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Two Carnot engines A and B are connected in series between two thermal reservoirs maintained at 1000 K and 100 K respectively. Engine A receives 1680 KJ of heat from high temperature reservoir and rejects heat to the carnot engine B. Engine B takes in heat rejection by engine A and rejects heat to the low temperature reservoir. If engine A and B deliver equal amount of work, the efficiencies of A and B engines are covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two Carnot engines A and B are connected in series between two thermal reservoirs maintained at 1000 K and 100 K respectively. Engine A receives 1680 KJ of heat from high temperature reservoir and rejects heat to the carnot engine B. Engine B takes in heat rejection by engine A and rejects heat to the low temperature reservoir. If engine A and B deliver equal amount of work, the efficiencies of A and B engines are.
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