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Find the distance of the point (3, – 2, 1) from the plane 2x – y + 2z + 3 = 0
  • a)
    17/3
  • b)
    19/3
  • c)
    13/3
  • d)
    15/3
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Find the distance of the point (3, – 2, 1) from the plane 2x &nd...
As we know that the length of the perpendicular from point P(x1,y1,z1) from the plane

Here, P(3, - 2,1) is the point and equation of Plane is 2x - y + 2z+3 = 0
Therefore, the perpendicular distance is :

 
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Find the distance of the point (3, – 2, 1) from the plane 2x – y + 2z + 3 = 0a)17/3b)19/3c)13/3d)15/3Correct answer is option 'C'. Can you explain this answer?
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