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Line segment AB is paralleled to another line segment CD. O is the mid point of AD. Show that triangle AOB congruent to Triangle DOC. O is the mid point of BC.
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Line segment AB is paralleled to another line segment CD. O is the mid...
Given: AB = CD ; O is the mid - point .

To proof : ABC is congruent to DOC

Proof : IN triangle AOB and DOC ,


AB = CD ( given )

<OAB = <ODC ( alternate interior angles )

<AOB = <DOC ( vertically opposite angles )

Therefore , triangle AOB is congruent to DOC (ASA rule )


OB = OC ( C.PC.CT)

Hence , O is also the mid point of BC
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Line segment AB is paralleled to another line segment CD. O is the mid...


Proof of Triangle Congruence: AOB ≅ DOC

1. Given Information:
- Line segment AB is parallel to line segment CD.
- O is the midpoint of segment AD.
- O is the midpoint of segment BC.

2. Reasoning:
- Since AB is parallel to CD, angle AOB is equal to angle DOC as corresponding angles.
- Triangle AOB and triangle DOC share a common side AO and DO.
- Also, O is the midpoint of both AD and BC, which implies that AO = OD and BO = OC.

3. Proof of Triangle Congruence:
- By Side-Angle-Side postulate, we have AO = OD (common side), angle AOB = angle DOC (corresponding angles), and BO = OC (midpoint property).
- Therefore, triangle AOB is congruent to triangle DOC by SAS congruence.

4. Conclusion:
- Triangle AOB is congruent to triangle DOC based on the given information and the properties of midpoints and parallel lines.
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Line segment AB is paralleled to another line segment CD. O is the mid point of AD. Show that triangle AOB congruent to Triangle DOC. O is the mid point of BC.
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