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For a BJT, find the maximum power dissipation when the device is safely operated at Vce = 90V and Ic = 0.5A
  • a)
    40 Watts
  • b)
    35 Watts
  • c)
    45 Watts
  • d)
    30 Watts
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
For a BJT, find the maximum power dissipation when the device is safel...
P=90*0.5=45Watts.
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For a BJT, find the maximum power dissipation when the device is safel...
Maximum Power Dissipation of a BJT

To find the maximum power dissipation of a BJT (Bipolar Junction Transistor), we need to consider the voltage across the collector-emitter junction (Vce) and the collector current (Ic). The maximum power dissipation occurs when the transistor is safely operated within its specified limits.

Given:
Vce = 90V
Ic = 0.5A

Calculating Maximum Power Dissipation:

To calculate the maximum power dissipation, we can use the formula:

Pmax = Vce × Ic

Substituting the given values:

Pmax = 90V × 0.5A
Pmax = 45 Watts

Therefore, the correct answer is option 'c' - 45 Watts.

Explanation:

The power dissipation of a BJT is the product of the voltage across the collector-emitter junction and the collector current. In this case, Vce is given as 90V and Ic is given as 0.5A.

By multiplying Vce and Ic, we can find the maximum power dissipation of the BJT. Substituting the given values into the formula, we get 45 Watts as the maximum power dissipation.

It is important to operate the transistor within its safe operating limits to prevent damage. Exceeding the maximum power dissipation can cause the device to overheat and potentially fail. Therefore, it is crucial to choose appropriate heatsinks and cooling mechanisms to ensure the BJT operates safely within its specified limits.
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