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Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O is
- a)E along AO
- b)2 E along AO
- c)E along BO
- d)E along CO
- e)zero
Correct answer is option 'A'. Can you explain this answer?
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Charges + 2q + q and +q are placed at the corners A,B and C of an equi...
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Charges + 2q + q and +q are placed at the corners A,B and C of an equi...
Given:
- Charges 2q, q, and q are placed at the corners A, B, and C of an equilateral triangle ABC.
- E is the electric field at the circumcentre O of the triangle, due to the charge q.
To find:
- The magnitude and direction of the resultant electric field at O.
Solution:
Step 1: Electric field due to charge q at O
- The electric field due to a point charge q at a distance r is given by the formula E = k*q/r^2, where k is the electrostatic constant.
- In an equilateral triangle, the circumcentre O is equidistant from all the three charges (A, B, C).
- Therefore, the magnitude of the electric field at O due to charge q at A is E1 = k*q/r1^2, where r1 is the distance between O and A.
- Similarly, the magnitude of the electric field at O due to charge q at B is E2 = k*q/r2^2, and due to charge q at C is E3 = k*q/r3^2.
Step 2: Analyzing the electric fields at O
- As all three charges are equidistant from O, the distances r1, r2, and r3 are equal, let's say r.
- Therefore, the magnitude of the electric field at O due to charge q at A, B, and C are E1 = k*q/r^2, E2 = k*q/r^2, and E3 = k*q/r^2 respectively.
- The direction of the electric field due to charge q at A is towards O, and the direction of the electric field due to charges q at B and C is away from O.
Step 3: Resultant electric field at O
- The resultant electric field at O is the vector sum of the electric fields due to charges q at A, B, and C.
- Since the electric fields due to charges q at B and C are equal in magnitude and opposite in direction, their vector sum is zero.
- Therefore, the resultant electric field at O is only due to the charge q at A, which is E = E1 = k*q/r^2.
- Thus, the magnitude of the resultant electric field at O is E, and its direction is along the line joining A and O.
Answer:
- The magnitude and direction of the resultant electric field at O is E along AO (option A).
- Charges 2q, q, and q are placed at the corners A, B, and C of an equilateral triangle ABC.
- E is the electric field at the circumcentre O of the triangle, due to the charge q.
To find:
- The magnitude and direction of the resultant electric field at O.
Solution:
Step 1: Electric field due to charge q at O
- The electric field due to a point charge q at a distance r is given by the formula E = k*q/r^2, where k is the electrostatic constant.
- In an equilateral triangle, the circumcentre O is equidistant from all the three charges (A, B, C).
- Therefore, the magnitude of the electric field at O due to charge q at A is E1 = k*q/r1^2, where r1 is the distance between O and A.
- Similarly, the magnitude of the electric field at O due to charge q at B is E2 = k*q/r2^2, and due to charge q at C is E3 = k*q/r3^2.
Step 2: Analyzing the electric fields at O
- As all three charges are equidistant from O, the distances r1, r2, and r3 are equal, let's say r.
- Therefore, the magnitude of the electric field at O due to charge q at A, B, and C are E1 = k*q/r^2, E2 = k*q/r^2, and E3 = k*q/r^2 respectively.
- The direction of the electric field due to charge q at A is towards O, and the direction of the electric field due to charges q at B and C is away from O.
Step 3: Resultant electric field at O
- The resultant electric field at O is the vector sum of the electric fields due to charges q at A, B, and C.
- Since the electric fields due to charges q at B and C are equal in magnitude and opposite in direction, their vector sum is zero.
- Therefore, the resultant electric field at O is only due to the charge q at A, which is E = E1 = k*q/r^2.
- Thus, the magnitude of the resultant electric field at O is E, and its direction is along the line joining A and O.
Answer:
- The magnitude and direction of the resultant electric field at O is E along AO (option A).
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Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer?
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Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer?.
Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Charges + 2q + q and +q are placed at the corners A,B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2 E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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