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Charges +2q +q and +q are placed at the corners A, B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O is
- a)E along AO
- b)2E along AO
- c)E along BO
- d)E along CO
- e)zero
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Charges +2q +q and +q are placed at the corners A, B and C of an equil...
The resultant electric field due to the two +q charges is (E cos60+E cos60)=E, Along AO
and the electric field due to the +2q charge, is 2E along AO but at the opposite direction of +2q from O... So the resultant electric field is (2E-E)=E Along AO but opp. direction of +2q from O.
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Charges +2q +q and +q are placed at the corners A, B and C of an equil...
The question asks about the magnitude and direction of the resultant electric field at the circumcentre O of the equilateral triangle ABC, due to the charges 2q, q, and q placed at the corners A, B, and C respectively.
To solve this problem, we need to calculate the electric field at point O due to each of the charges separately and then find the resultant.
Electric Field due to a Point Charge:
The electric field at a point due to a point charge is given by the formula:
E = k * q / r^2
where E is the electric field, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), q is the charge, and r is the distance between the charge and the point where the electric field is being calculated.
Electric Field at Point O due to Charge q:
To find the electric field at point O due to the charge q at point B, we need to calculate the electric field at O using the formula mentioned above. Since point O is equidistant from points A, B, and C, the distance between charge q and point O is the same as the distance between charge q and point A or C.
Therefore, the electric field at point O due to charge q is the same as the electric field at point O due to charge q at points A and C.
Electric Field at Point O due to Charge 2q:
To find the electric field at point O due to the charge 2q at point A, we again use the formula mentioned above. Since the charge is at point A, the distance between charge 2q and point O is different from the distance between charge 2q and point B or C.
Resultant Electric Field at Point O:
Since the electric field at point O due to charge q is the same as the electric field at point O due to charge q at points A and C, and the electric field at point O due to charge 2q is different, we need to find the vector sum of the electric fields at point O due to charges q and 2q.
Since the charges are placed at the corners of an equilateral triangle, the vectors representing the electric fields at point O due to charges q and 2q have the same magnitude but opposite directions. Therefore, the resultant electric field at point O is the vector sum of these two electric fields, which results in a single electric field with the same magnitude as the individual electric fields but in the direction from O to B (from q to 2q).
Therefore, the correct answer is option 'A': The magnitude and direction of the resultant electric field at point O is E along AO.
To solve this problem, we need to calculate the electric field at point O due to each of the charges separately and then find the resultant.
Electric Field due to a Point Charge:
The electric field at a point due to a point charge is given by the formula:
E = k * q / r^2
where E is the electric field, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), q is the charge, and r is the distance between the charge and the point where the electric field is being calculated.
Electric Field at Point O due to Charge q:
To find the electric field at point O due to the charge q at point B, we need to calculate the electric field at O using the formula mentioned above. Since point O is equidistant from points A, B, and C, the distance between charge q and point O is the same as the distance between charge q and point A or C.
Therefore, the electric field at point O due to charge q is the same as the electric field at point O due to charge q at points A and C.
Electric Field at Point O due to Charge 2q:
To find the electric field at point O due to the charge 2q at point A, we again use the formula mentioned above. Since the charge is at point A, the distance between charge 2q and point O is different from the distance between charge 2q and point B or C.
Resultant Electric Field at Point O:
Since the electric field at point O due to charge q is the same as the electric field at point O due to charge q at points A and C, and the electric field at point O due to charge 2q is different, we need to find the vector sum of the electric fields at point O due to charges q and 2q.
Since the charges are placed at the corners of an equilateral triangle, the vectors representing the electric fields at point O due to charges q and 2q have the same magnitude but opposite directions. Therefore, the resultant electric field at point O is the vector sum of these two electric fields, which results in a single electric field with the same magnitude as the individual electric fields but in the direction from O to B (from q to 2q).
Therefore, the correct answer is option 'A': The magnitude and direction of the resultant electric field at point O is E along AO.
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Charges +2q +q and +q are placed at the corners A, B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer?
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Charges +2q +q and +q are placed at the corners A, B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Charges +2q +q and +q are placed at the corners A, B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Charges +2q +q and +q are placed at the corners A, B and C of an equilateral triangle ABC. If E is the electric field at the circumcentre O of the triangle, due to the charge +q, then the magnitude and direction of the resulatant electric field at O isa)E along AOb)2E along AOc)E along BOd)E along COe)zeroCorrect answer is option 'A'. Can you explain this answer?.
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