CAT Exam > CAT Questions > Applicants for the doctoral programmes of Amb...
Start Learning for Free
Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.
For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:
1. No one is below the 80th percentile in all 3 sections.
2. 150 are at or above the 80th percentile in exactly two sections.
3. The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.
4. Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:
Number of candidates below 80th percentile in M = 4:2:1.
BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.
Q.
If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?
Correct answer is '170'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Applicants for the doctoral programmes of Ambi Institute of Engineerin...
We can see that, 200 candidates scored above 90th percentile overall in CET. Let the following Venn diagram represent the number of persons who scored above 80 percentile in CET in each of the three sections:
From 1, h = 0.
From 2, d + e + f = 150
From 3, a = b = c
We know, there are a total of 200 candidates,
3a + g = 200 – 150 = 50
From 4, (2a + f) : (2a + e) : (2a + d) = 4 : 2 : 1
So, 6a + (d + e + f) is divisible by 4 + 2 + 1 = 7.
Now, since d + e + f = 150, 6a + 150 is divisible by 7, i.e.,
(6a + 3) is divisible by 7.
Hence, a = 3, 10, 17,. . .
Further, since 3a + g = 50, a < 17. Hence, only two values are possible for a, 3 or 10. We can calculate the values of the other variables for the two cases. a = 3 or 10 d = 18 or 10 e = 42 or 40 f = 90 or 100 g = 41 or 20 From the candidates who are at or above 90th percentile, the candidates who are at or above 80th percentile in at least two sections are selected for AET. Hence, the candidates represented by d, e, f and g are selected for AET. BIE will consider the candidates who are appearing for AET and are at or above 80th percentile in P. Hence, BIE will consider the candidates represented by d, e and g, which can be 104 or 80. BIE will conduct a separate test for the other students who are at or above 80th percentile in P. Given that there are a total of 400 candidates at or above 80th percentile in P, and since there are 104 or 80 candidates at or above 80th percentile in P and are at or above 90th percentile overall, there must be 296 or 320 candidates at or above 80th percentile in P who scored less than 90th percentile overall.
From 2, d + e + f = 150
From 3, a = b = c
We know, there are a total of 200 candidates,
3a + g = 200 – 150 = 50
From 4, (2a + f) : (2a + e) : (2a + d) = 4 : 2 : 1
So, 6a + (d + e + f) is divisible by 4 + 2 + 1 = 7.
Now, since d + e + f = 150, 6a + 150 is divisible by 7, i.e.,
(6a + 3) is divisible by 7.
Hence, a = 3, 10, 17,. . .
Further, since 3a + g = 50, a < 17. Hence, only two values are possible for a, 3 or 10. We can calculate the values of the other variables for the two cases. a = 3 or 10 d = 18 or 10 e = 42 or 40 f = 90 or 100 g = 41 or 20 From the candidates who are at or above 90th percentile, the candidates who are at or above 80th percentile in at least two sections are selected for AET. Hence, the candidates represented by d, e, f and g are selected for AET. BIE will consider the candidates who are appearing for AET and are at or above 80th percentile in P. Hence, BIE will consider the candidates represented by d, e and g, which can be 104 or 80. BIE will conduct a separate test for the other students who are at or above 80th percentile in P. Given that there are a total of 400 candidates at or above 80th percentile in P, and since there are 104 or 80 candidates at or above 80th percentile in P and are at or above 90th percentile overall, there must be 296 or 320 candidates at or above 80th percentile in P who scored less than 90th percentile overall.
In this case, g = 20. Number of candidates shortlisted for AET = d + e + f + g = 10 + 40 + 100 + 20 = 170
Answer: 170
Answer: 170
Most Upvoted Answer
Applicants for the doctoral programmes of Ambi Institute of Engineerin...
Given Information:
- CET has three sections: Physics (P), Chemistry (C), and Maths (M).
- Candidates at or above the 80th percentile in at least two sections and at or above the 90th percentile overall are selected for AET by AIE.
- For BIE selection, candidates appearing in AET by AIE with 80th percentile in P are considered, others have to take a separate test.
- Total candidates at or above 80th percentile in P = 400.
Analysis:
- Total candidates at or above the 90th percentile overall = 200.
- No one is below the 80th percentile in all 3 sections.
- 150 candidates are at or above the 80th percentile in exactly two sections.
- Number of candidates below 80th percentile in P: C: M = 4:2:1.
Solution:
- Let the number of candidates at or above the 80th percentile in all three sections be x.
- Total candidates at or above 80th percentile only in one section = (400 - x).
- According to the given information, the number of candidates shortlisted for AET by AIE would be:
- (x + 150) = 200, as 200 candidates are at or above 90th percentile overall.
- x = 50, which means 50 candidates are at or above 80th percentile in all three sections.
- Since the number of candidates at or above the 90th percentile overall and also at or above the 80th percentile in all three sections is a multiple of 5, the total number of candidates shortlisted for AET by AIE = x = 50 + 120 = 170.
Therefore, 170 candidates were shortlisted for the AET by AIE.
Attention CAT Students!
To make sure you are not studying endlessly, EduRev has designed CAT study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CAT.
|
Explore Courses for CAT exam
|
|
Similar CAT Doubts
Top Courses for CATView all
Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer?
Question Description
Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer?.
Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer?.
Solutions for Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer? in English & in Hindi are available as part of our courses for CAT.
Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free.
Here you can find the meaning of Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer?, a detailed solution for Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer? has been provided alongside types of Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET:1.No one is below the 80th percentile in all 3 sections.2. 150 are at or above the 80th percentile in exactly two sections.3.The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M.4.Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C:Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.Q.If the number of candidates who are at or above the 90th percentile overall and also at or above the 80th percentile in all three sections in GET is actually a multiple of 5, then how many candidates were shortlisted for the AET for AIE?Correct answer is '170'. Can you explain this answer? tests, examples and also practice CAT tests.
|
|
Explore Courses for CAT exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup