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∫ (tan x + cot x) dx is equal to
- a)log | sin x + cos x|
- b)log | cot x|
- c)log | tan x|
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
∫(tan x + cot x) dx is equal toa)log|sinx+cosx|b)log|cotx|c)log|ta...
[-log | cos x | + log |sin x|] = log |tan x|
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∫(tan x + cot x) dx is equal toa)log|sinx+cosx|b)log|cotx|c)log|ta...
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∫(tan x + cot x) dx is equal toa)log|sinx+cosx|b)log|cotx|c)log|tanx|d)none of theseCorrect answer is option 'C'. Can you explain this answer?
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