JEE Exam > JEE Questions > The general solution of the differential equa...
Start Learning for Free
The general solution of the differential equation (1+tany)(dx−dy)+2xdy=0 is
- a)x(siny+cosy)=siny+cey
- b)x(siny+cosy)=siny+ce−y
- c)y(sinx+cosx)=sinx+cex
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The general solution of the differential equation(1+tany)(dx−dy)...
It seems like the equation you provided is incomplete. Could you please provide the full equation?
Free Test
FREE
| Start Free Test |
Community Answer
The general solution of the differential equation(1+tany)(dx−dy)...
We have, (1+tany)(dx−dy)+2xdy=0
⇒(1+tany)dx=(1+tany−2x)dy
It is a linear differential equation.
=(cosy+siny)ey
So, the solution is
xey (sin y + cos y) = ∫ey (sin y + cos y)dy + c
⇒ xey(sin y+cos y)=eysin y + c
⇒ x(sin y + cos y) = sin y + ce−y.
⇒(1+tany)dx=(1+tany−2x)dy
It is a linear differential equation.
=(cosy+siny)ey
So, the solution is
xey (sin y + cos y) = ∫ey (sin y + cos y)dy + c
⇒ xey(sin y+cos y)=eysin y + c
⇒ x(sin y + cos y) = sin y + ce−y.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer?
Question Description
The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer?.
The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The general solution of the differential equation(1+tany)(dx−dy)+2xdy=0 isa)x(siny+cosy)=siny+ceyb)x(siny+cosy)=siny+ce−yc)y(sinx+cosx)=sinx+cexd)None of theseCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup