Mechanical Engineering Exam  >  Mechanical Engineering Questions  >  According to the maximum shear stress theory ... Start Learning for Free
According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:
[IES-1998: ISRO-2008]
  • a)
    T/2
  • b)
    T
  • c)
    √2T
  • d)
    2T
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
According to the maximum shear stress theory of failure, permissible t...
  principalstressesfor only thisshear stressare 
  maximum principal stress theory of failuregives
View all questions of this test
Most Upvoted Answer
According to the maximum shear stress theory of failure, permissible t...
Explanation:
The maximum shear stress theory of failure states that failure occurs when the maximum shear stress in a material exceeds the shear strength of the material. The formula for maximum shear stress in a circular shaft is:

τmax = T*c/J

where T is the twisting moment, c is the distance from the center of the shaft to the outer surface, and J is the polar moment of inertia of the shaft.

According to this theory, the permissible twisting moment is T.

The maximum principal stress theory of failure states that failure occurs when the maximum principal stress in a material exceeds the tensile or compressive strength of the material. The formula for maximum principal stress in a circular shaft is:

σmax = M*c/I

where M is the bending moment, c is the distance from the center of the shaft to the outer surface, and I is the moment of inertia of the shaft.

To relate this to twisting moment, we can use the torsion-bending equation:

M = T*(d/2)

where d is the diameter of the shaft.

Substituting this into the formula for maximum principal stress, we get:

σmax = T*c/(π/32)*d^3

The permissible twisting moment according to this theory is when σmax equals the tensile or compressive strength of the material.

Since the maximum shear stress theory gives a lower permissible twisting moment than the maximum principal stress theory, we can use the ratio of their formulas to find the permissible twisting moment according to the maximum principal stress theory:

(T/2)*c/J / (T*c/(π/32)*d^3) = 2/(π*d^2)

Multiplying both sides by T gives:

(T/2)*c/J = (2T*c)/(π*d^3)

Simplifying:

T/2 = π*d^3/(2J)

Multiplying both sides by 2 gives:

T = 2*π*d^3/J

Therefore, the permissible twisting moment according to the maximum principal stress theory is 2T, or option D.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
Explore Courses for Mechanical Engineering exam

Top Courses for Mechanical Engineering

According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer?
Question Description
According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer?.
Solutions for According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice According to the maximum shear stress theory of failure, permissible twisting moment in a circular shaft is 'T'. The permissible twisting moment will the same shaft as per the maximum principal stress theory of failure will be:[IES-1998: ISRO-2008]a)T/2b)Tc)√2Td)2TCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
Explore Courses for Mechanical Engineering exam

Top Courses for Mechanical Engineering

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev