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A bag contains 5 white and 3 black balls. Two balls are drawn at random one after the other without replacement. Find the probability of drawing a black ball in the first second attempt respectively.?
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A bag contains 5 white and 3 black balls. Two balls are drawn at rando...
**Problem Statement**

A bag contains 5 white and 3 black balls. Two balls are drawn at random one after the other without replacement. Find the probability of drawing a black ball in the first and second attempt respectively.

**Solution**

Let's first find the probability of drawing a black ball on the first attempt.

**Probability of drawing a black ball on the first attempt**

Total number of balls = 8

Total number of black balls = 3

Therefore, the probability of drawing a black ball on the first attempt = 3/8

Now, let's find the probability of drawing a black ball on the second attempt after a black ball was drawn in the first attempt.

**Probability of drawing a black ball on the second attempt after a black ball was drawn in the first attempt**

Total number of balls = 7

Total number of black balls = 2

Since we have already drawn a black ball in the first attempt, the total number of balls reduces to 7. Also, the number of black balls reduces to 2 as we do not replace the ball.

Therefore, the probability of drawing a black ball on the second attempt after a black ball was drawn in the first attempt = 2/7

We can also find the probability of drawing a black ball on the second attempt after a white ball was drawn in the first attempt.

**Probability of drawing a black ball on the second attempt after a white ball was drawn in the first attempt**

Total number of balls = 7

Total number of black balls = 3

Since we have already drawn a white ball in the first attempt, the total number of balls reduces to 7. However, the number of black balls remains the same at 3.

Therefore, the probability of drawing a black ball on the second attempt after a white ball was drawn in the first attempt = 3/7

**Conclusion**

- The probability of drawing a black ball on the first attempt = 3/8
- The probability of drawing a black ball on the second attempt after a black ball was drawn in the first attempt = 2/7
- The probability of drawing a black ball on the second attempt after a white ball was drawn in the first attempt = 3/7
Community Answer
A bag contains 5 white and 3 black balls. Two balls are drawn at rando...
Required probability = 3/8 × 2/7
= 3/28
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A bag contains 5 white and 3 black balls. Two balls are drawn at random one after the other without replacement. Find the probability of drawing a black ball in the first second attempt respectively.?
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A bag contains 5 white and 3 black balls. Two balls are drawn at random one after the other without replacement. Find the probability of drawing a black ball in the first second attempt respectively.? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about A bag contains 5 white and 3 black balls. Two balls are drawn at random one after the other without replacement. Find the probability of drawing a black ball in the first second attempt respectively.? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bag contains 5 white and 3 black balls. Two balls are drawn at random one after the other without replacement. Find the probability of drawing a black ball in the first second attempt respectively.?.
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