A bag contains 5 white and 3 black balls. Two balls are drawn at rando...
**Problem Statement**
A bag contains 5 white and 3 black balls. Two balls are drawn at random one after the other without replacement. Find the probability of drawing a black ball in the first and second attempt respectively.
**Solution**
Let's first find the probability of drawing a black ball on the first attempt.
**Probability of drawing a black ball on the first attempt**
Total number of balls = 8
Total number of black balls = 3
Therefore, the probability of drawing a black ball on the first attempt = 3/8
Now, let's find the probability of drawing a black ball on the second attempt after a black ball was drawn in the first attempt.
**Probability of drawing a black ball on the second attempt after a black ball was drawn in the first attempt**
Total number of balls = 7
Total number of black balls = 2
Since we have already drawn a black ball in the first attempt, the total number of balls reduces to 7. Also, the number of black balls reduces to 2 as we do not replace the ball.
Therefore, the probability of drawing a black ball on the second attempt after a black ball was drawn in the first attempt = 2/7
We can also find the probability of drawing a black ball on the second attempt after a white ball was drawn in the first attempt.
**Probability of drawing a black ball on the second attempt after a white ball was drawn in the first attempt**
Total number of balls = 7
Total number of black balls = 3
Since we have already drawn a white ball in the first attempt, the total number of balls reduces to 7. However, the number of black balls remains the same at 3.
Therefore, the probability of drawing a black ball on the second attempt after a white ball was drawn in the first attempt = 3/7
**Conclusion**
- The probability of drawing a black ball on the first attempt = 3/8
- The probability of drawing a black ball on the second attempt after a black ball was drawn in the first attempt = 2/7
- The probability of drawing a black ball on the second attempt after a white ball was drawn in the first attempt = 3/7
A bag contains 5 white and 3 black balls. Two balls are drawn at rando...
Required probability = 3/8 × 2/7
= 3/28
To make sure you are not studying endlessly, EduRev has designed CA Foundation study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CA Foundation.