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Determine the third velocity component such that continuity equation is satisfied if two components are u=x2+y2+z2, v=xy2 – yz2 + xy 

  • a)
    -3xz-2xyz+z2/3+f(y,z)

  • b)
    -3xz+2xyz+z3/3+f(y,z)

  • c)
    -3xz-2xyz+z3/3+f(x,z)

  • d)
    -3xz-2xyz+z3/3+f(x,y)

Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Determine the third velocity component such that continuity equation i...
Explanation: The continuity equation for incompressible is du/dx+dv/dy+dw/dz = 0.

Here du/dx=2x and v=2xy-z2

On solving by integrating, we get w = -3xz-2xyz+z3/3+f(x,y),
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Most Upvoted Answer
Determine the third velocity component such that continuity equation i...
Z2 and the flow is incompressible.

The continuity equation for an incompressible flow is:

∇·v = ∂u/∂x + ∂v/∂y + ∂w/∂z = 0

where v = (u, v, w) is the velocity vector.

Given u = x^2y^2z^2 and v = xy^2z^2, we can calculate the third component of the velocity vector as follows:

∂w/∂z = - (∂u/∂x + ∂v/∂y)

Taking partial derivatives of u and v with respect to x and y, we get:

∂u/∂x = 2xy^2z^2

∂v/∂y = 2xyz^2

Substituting these values into the continuity equation, we get:

∂w/∂z = - (2xy^2z^2 + 2xyz^2)

Integrating both sides with respect to z, we get:

w = -xy^2z^3 - xyz^3 + f(x,y)

where f(x,y) is an arbitrary function of x and y.

Therefore, the third component of the velocity vector is:

w = -xy^2z^3 - xyz^3 + f(x,y)

where f(x,y) is an arbitrary function of x and y.
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Determine the third velocity component such that continuity equation is satisfied if two components are u=x2+y2+z2, v=xy2– yz2+ xya)-3xz-2xyz+z2/3+f(y,z)b)-3xz+2xyz+z3/3+f(y,z)c)-3xz-2xyz+z3/3+f(x,z)d)-3xz-2xyz+z3/3+f(x,y)Correct answer is option 'D'. Can you explain this answer?
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