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When during electrolysis of a solution of AgNO3 ,9650 C of charge pass through the electroplating bath,the mass of silver deposited on the cathode will be
  • a)
    1.08 g
  • b)
    10.8 g
  • c)
    12.6 g
  • d)
    1.8 g
Correct answer is option 'B'. Can you explain this answer?
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When during electrolysis of a solution of AgNO3 ,9650 C of charge pass...
Given:
Charge passed (Q) = 9650 C
Electrochemical equivalent of silver (E) = 0.001118 g/C

We know that the mass of a substance deposited on an electrode during electrolysis is given by the equation:

Mass (m) = Q x E

Calculation:
Substituting the given values in the above equation, we get:

m = 9650 C x 0.001118 g/C = 10.8 g

Therefore, the mass of silver deposited on the cathode will be 10.8 g.

Answer: Option B
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