JEE Exam  >  JEE Questions  >  The slope of the normal to the curvex = a (co... Start Learning for Free
The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ is
  • a)
    tan θ
  • b)
    – cot θ.
  • c)
    – tan θ
  • d)
    cot θ
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The slope of the normal to the curvex = a (cos θ + θ sin &...
View all questions of this test
Most Upvoted Answer
The slope of the normal to the curvex = a (cos θ + θ sin &...
Free Test
Community Answer
The slope of the normal to the curvex = a (cos θ + θ sin &...
Explore Courses for JEE exam
The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer?
Question Description
The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer?.
Solutions for The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The slope of the normal to the curvex = a (cos θ + θ sin θ),y = a (sin θ – θ cos θ) at any point ‘θ’ isa)tan θb)– cot θ.c)– tan θd)cot θCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev