To find the equation of the tangent to the curve y = (4x^2)^(2/3) at x = 2, we need to follow these steps:

1. Find the derivative of the curve:
The derivative of y with respect to x can be found using the chain rule. Let's denote y as u^(2/3), where u = 4x^2.
dy/dx = (2/3) * u^(-1/3) * du/dx
= (2/3) * (4x^2)^(-1/3) * d(4x^2)/dx
= (2/3) * (4x^2)^(-1/3) * 8x
= (16/3) * (x^(-2/3)) * x
= (16/3) * x^(1/3)

2. Find the slope of the tangent line:
To find the slope of the tangent line at x = 2, substitute x = 2 into the derivative:
dy/dx = (16/3) * 2^(1/3)
= (16/3) * (∛2)

3. Find the y-coordinate of the point on the curve at x = 2:
Substitute x = 2 into the original equation y = (4x^2)^(2/3):
y = (4 * 2^2)^(2/3)
= (4 * 4)^(2/3)
= 16^(2/3)
= 4^2
= 16

4. Use the point-slope form of a line:
The equation of a line with slope m passing through the point (x1, y1) is given by:
y - y1 = m(x - x1)

Substituting the values we found:
y - 16 = (16/3) * (∛2)(x - 2)

5. Simplify the equation:
y - 16 = (16/3) * (∛2)x - (16/3) * (∛2) * 2
y - 16 = (16/3) * (∛2)x - (32/3) * (∛2)
y = (16/3) * (∛2)x - (32/3) * (∛2) + 16

Thus, the equation of the tangent to the curve y = (4x^2)^(2/3) at x = 2 is y = (16/3) * (∛2)x - (32/3) * (∛2) + 16, which can be simplified as y = (16/3) * (∛2)x - (32/3) * (∛2/3) + 16. The correct answer is option 'A', x = 2, which is not the correct equation of the tangent.