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A uniform body of size 4 m long * 2.5 m wide * 1.5 m deep floats in water. What is the weight of the body if depth of immersion is 1.5 m ?

  • a)
    147.1 kN

  • b)
    294.3 kN

  • c)
    73.5 kN

  • d)
    588.6 kN

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A uniform body of size 4 m long * 2.5 m wide * 1.5 m deep floats in wa...
Explanation: Weight of Body = Weight of water displaced

= ρ*g*Volume of displaced water=9.81*1000*4*2.5*1.5=147.1kN.
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Most Upvoted Answer
A uniform body of size 4 m long * 2.5 m wide * 1.5 m deep floats in wa...
The weight of a body floating in water can be determined using Archimedes' principle, which states that the buoyant force acting on a body is equal to the weight of the fluid displaced by the body.

In this case, the body is floating in water, so the buoyant force acting on it is equal to its weight. We can calculate the weight of the body using the formula:

Weight = Volume × Density × g

Where:
- Volume is the volume of the body (length × width × depth of immersion)
- Density is the density of water (1000 kg/m³)
- g is the acceleration due to gravity (9.81 m/s²)

Let's calculate the weight of the body step by step:

1. Calculate the volume of the body:
Volume = 4 m × 2.5 m × 1.5 m = 15 m³

2. Calculate the weight:
Weight = Volume × Density × g
= 15 m³ × 1000 kg/m³ × 9.81 m/s²

Converting units:
Weight = 15 m³ × 1000 kg/m³ × 9.81 m/s² / 1000 N/kN
= 147.15 kN

Therefore, the weight of the body is approximately 147.1 kN.

So, the correct answer is option A) 147.1 kN.
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A uniform body of size 4 m long * 2.5 m wide * 1.5 m deep floats in water. What is the weight of the body if depth of immersion is 1.5 m ?a)147.1 kNb)294.3 kNc)73.5 kNd)588.6 kNCorrect answer is option 'A'. Can you explain this answer?
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