**Plotting a Graph for the Linear Equation 3x - 5y + 7 = 0**

To plot a graph for the linear equation 3x - 5y + 7 = 0, we need to find four values of x and their corresponding values of y that satisfy the equation. By selecting different values for x, we can find the corresponding y-values and then plot these points on a graph to visualize the equation.

Let's choose four values for x and find their corresponding y-values:

1. When x = 0:
Substitute x = 0 into the equation: 3(0) - 5y + 7 = 0
Simplifying the equation: -5y + 7 = 0
Subtract 7 from both sides: -5y = -7
Divide by -5: y = 7/5

Therefore, when x = 0, y = 7/5. The first point is (0, 7/5).

2. When x = 1:
Substitute x = 1 into the equation: 3(1) - 5y + 7 = 0
Simplifying the equation: 3 - 5y + 7 = 0
Combine like terms: -5y + 10 = 0
Subtract 10 from both sides: -5y = -10
Divide by -5: y = 2

Therefore, when x = 1, y = 2. The second point is (1, 2).

3. When x = -1:
Substitute x = -1 into the equation: 3(-1) - 5y + 7 = 0
Simplifying the equation: -3 - 5y + 7 = 0
Combine like terms: -5y + 4 = 0
Subtract 4 from both sides: -5y = -4
Divide by -5: y = 4/5

Therefore, when x = -1, y = 4/5. The third point is (-1, 4/5).

4. When x = 2:
Substitute x = 2 into the equation: 3(2) - 5y + 7 = 0
Simplifying the equation: 6 - 5y + 7 = 0
Combine like terms: -5y + 13 = 0
Subtract 13 from both sides: -5y = -13
Divide by -5: y = 13/5

Therefore, when x = 2, y = 13/5. The fourth point is (2, 13/5).

Now, let's plot these four points on a graph:

- Mark the x-axis and y-axis with appropriate scales.
- Locate the first point (0, 7/5) on the graph.
- Locate the second point (1, 2) on the graph.
- Locate the third point (-1, 4/5) on the graph.
- Locate the fourth point (2, 13/5) on the graph.
- Connect these points with a straight line.

The resulting line represents the graph of the linear equation 3x - 5y + 7 =

what's ur profit.. how's u know what the graph is ?